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What is the difference between integration and unit tests?
...ure are green because, by using mocks, they removed dependencies. In other words, they run in an ideal, completely fictional world. And this is the only way to isolate bugs and seek them. Unit testing means mocking. If you aren't mocking, you aren't unit testing.
The difference
Integration tests t...
How to split a String by space
...plit your string into tokens.
As a side note, I'm not sure "splited" is a word :) I believe the state of being the victim of a split is also "split". It's one of those tricky grammar things :-) Not trying to be picky, just figured I'd pass it on!
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SQL Server: Make all UPPER case to Proper Case/Title Case
...
This function:
"Proper Cases" all "UPPER CASE" words that are delimited by white space
leaves "lower case words" alone
works properly even for non-English alphabets
is portable in that it does not use fancy features of recent SQL server versions
can be easily changed to u...
Truncate a string straight JavaScript
...ipt. It's a url, so there are no spaces, and I obviously don't care about word boundaries, just characters.
9 Answers
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Replace multiple strings with multiple other strings
I'm trying to replace multiple words in a string with multiple other words. The string is "I have a cat, a dog, and a goat."
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Ruby capitalize every word first letter
I need to make the first character of every word uppercase, and make the rest lowercase...
8 Answers
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淘宝网采用什么技术架构来实现网站高负载的 - 更多技术 - 清泛网 - 专注C/C...
... 息的话，那么当保存状态信息的server宕机的时候，我们怎么办?通常来说，我们都是通过集群来解决这个问题，而通常所说的集群，不仅有负载均衡，更重要的是要有失效恢复failover,比如tomcat采 用的集群节点广播复制，jboss采 用...
“Ago” date/time functions in Ruby/Rails
...2.days.since
Or in your views you have the helpers:
distance_of_time_in_words(from_time, to_time)
time_ago_in_words(from_time)
Check the API for details and more options.
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Javascript reduce on array of objects
...ningful reductions for other n:1 relationship problems.
Removing repeated words:
const skipIfAlreadyFound = (words, word) => words.includes(word)
? words
: words.concat(word);
const deduplicatedWords = aBunchOfWords.reduce(skipIfAlreadyFound, []);
Providing a count of all words found...
Fixed Table Cell Width
...er didn't get any votes and I didn't want users to ignore it. However, the word-break suggestion isn't necessary unless that's what you're aiming for.
– thebdawk05
Jul 29 '13 at 18:12
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