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What is the difference between Ruby 1.8 and Ruby 1.9

..."cat"[1] => 97 {"a","b"} No Longer Supported Ruby 1.9 irb(main):002:0> {1,2} SyntaxError: (irb):2: syntax error, unexpected ',', expecting tASSOC Ruby 1.8.6 irb(main):001:0> {1,2} => {1=>2} Action: Convert to {1 => 2} Array.to_s Now Contains Punctuation Ruby 1.9 irb...
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How to drop columns by name in a data frame

... or the subset function. For example : R> df <- data.frame(x=1:5, y=2:6, z=3:7, u=4:8) R> df x y z u 1 1 2 3 4 2 2 3 4 5 3 3 4 5 6 4 4 5 6 7 5 5 6 7 8 Then you can use the which function and the - operator in column indexation : R> df[ , -which(names(df) %in% c("z","u"))] x y 1 1...
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Why does 2 mod 4 = 2?

... 152 Mod just means you take the remainder after performing the division. Since 4 goes into 2 zero ti...
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Shuffle two list at once with same order

...t pre-processing. But there is problem, in lists documents and documents2 I have the same documents and I need shuffle them in order to keep same order in both lists. I cannot shuffle them separately because each time I shuffle the list, I get other results. That is why I need to shuffle the at ...
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Python creating a dictionary of lists

... 286 You can use defaultdict: >>> from collections import defaultdict >>> d = de...
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WinDBG用法详解 PDF - 文档下载 - 清泛网 - 专注C/C++及内核技术

.....................................................................1 30.1.2内容............................................................................................................................2 30.1.3存储.................................................................................
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How to select rows from a DataFrame based on column values?

... three'.split(), 'C': np.arange(8), 'D': np.arange(8) * 2}) print(df) # A B C D # 0 foo one 0 0 # 1 bar one 1 2 # 2 foo two 2 4 # 3 bar three 3 6 # 4 foo two 4 8 # 5 bar two 5 10 # 6 foo one 6 12 # 7 foo three 7 14 pri...
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Getting key with maximum value in dictionary?

... 25 Answers 25 Active ...
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Filtering a list based on a list of booleans

...ss: >>> from itertools import compress >>> list_a = [1, 2, 4, 6] >>> fil = [True, False, True, False] >>> list(compress(list_a, fil)) [1, 4] Timing comparisons(py3.x): >>> list_a = [1, 2, 4, 6] >>> fil = [True, False, True, False] >>&gt...
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How to get a specific output iterating a hash in Ruby?

... 328 hash.each do |key, array| puts "#{key}-----" puts array end Regarding order I should add,...