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How to sort two lists (which reference each other) in the exact same way
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13 Answers
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Extract first item of each sublist
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Using list comprehension:
>>> lst = [['a','b','c'], [1,2,3], ['x','y','z']]
>>> lst2 = [item[0] for item in lst]
>>> lst2
['a', 1, 'x']
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LISTAGG in Oracle to return distinct values
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edited Apr 13 '19 at 23:57
Jon Heller
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Remove all the elements that occur in one list from another
...e following statement does exactly what you want and stores the result in l3:
l3 = [x for x in l1 if x not in l2]
l3 will contain [1, 6].
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All but last element of Ruby array
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130
Perhaps...
a = t # => [1, 2, 3, 4]
a.first a.size - 1 # => [1, 2, 3]
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Delete an element from a dictionary
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answered Apr 30 '11 at 21:25
Greg HewgillGreg Hewgill
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Find value in an array
...rray, and if that's the case, you can use Array#include?(value):
a = [1,2,3,4,5]
a.include?(3) # => true
a.include?(9) # => false
If you mean something else, check the Ruby Array API
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Error installing libv8: ERROR: Failed to build gem native extension
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try this one:
gem install libv8 -v '3.16.14.3' -- --with-system-v8
Note : Because libv8 is the interface for the V8 engine used by therubyracer,
you may need to use libv8, even if you have V8 installed already. If
you wish to use your own V8 installat...
python pandas remove duplicate columns
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edited Aug 23 '19 at 13:30
Jean-François Corbett
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How to index into a dictionary?
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Dictionaries are unordered in Python versions up to and including Python 3.6. If you do not care about the order of the entries and want to access the keys or values by index anyway, you can use d.keys()[i] and d.values()[i] or d.items()[i]. (Note that these methods create a list of all keys, va...