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Javascript: How to loop through ALL DOM elements on a page?

...ments in a page: var all = document.getElementsByTagName("*"); for (var i=0, max=all.length; i < max; i++) { // Do something with the element here } Note that you could use querySelectorAll(), if it's available (IE9+, CSS in IE8), to just find elements with a particular class. if (document...
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How to inspect FormData?

... 320 Updated Method: As of March 2016, recent versions of Chrome and Firefox now support using FormD...
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Circle-Rectangle collision detection (intersection)

...ods will work, but for a rectangle you can just check whether this works: 0 ≤ AP·AB ≤ AB·AB and 0 ≤ AP·AD ≤ AD·AD And intersectCircle() is easy to implement too: one way would be to check if the foot of the perpendicular from P to the line is close enough and between the endpoints, an...
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Remote debugging with Android emulator

...lator takes the next available even+odd port number tuple (up to around 5580, I think). For reference, I did the following steps on my local machine: ssh -NL 5554:localhost:5554 -L 5555:localhost:5555 myuser@remote-server killall adb; adb devices I believe the emulator tries to notify a local a...
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ORA-00979 not a group by expression

I am getting ORA-00979 with the following query: 8 Answers 8 ...
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Regular expression to match standard 10 digit phone number

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Named string formatting in C#

... 130 There is no built-in method for handling this. Here's one method string myString = "{foo} is {...
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How can I use an http proxy with node.js http.Client?

...y. var http = require("http"); var options = { host: "proxy", port: 8080, path: "http://www.google.com", headers: { Host: "www.google.com" } }; http.get(options, function(res) { console.log(res); res.pipe(process.stdout); }); For the record his answer does work with http://node...
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How to validate a url in Python? (Malformed or not)

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Dynamically creating keys in a JavaScript associative array

...() var keyValuePair = text.replace(/ /g,'').split('='); dict[ keyValuePair[0] ] = keyValuePair[1]; alert( dict[keyValuePair[0]] ); share | improve this answer | follow ...