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Random record from MongoDB
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Do a count of all records, generate a random number between 0 and the count, and then do:
db.yourCollection.find().limit(-1).skip(yourRandomNumber).next()
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How to understand nil vs. empty vs. blank in Ruby
...ed on any object and is true if the object is nil.
.empty? can be used on strings, arrays and hashes and returns true if:
String length == 0
Array length == 0
Hash length == 0
Running .empty? on something that is nil will throw a NoMethodError.
That is where .blank? comes in. It is implemented...
Converting java.util.Properties to HashMap
...lements Map<Object, Object>). You attempt to feed that into a Map<String, String>. It is therefore incompatible.
You need to feed string properties one by one into your map...
For instance:
for (final String name: properties.stringPropertyNames())
map.put(name, properties.getPrope...
String Resource new line /n not possible?
... doesn't seem like it's possible to add a new line /n to an XML resource string. Is there another way of doing this?
10 A...
Is there “0b” or something similar to represent a binary number in Javascript
...nd octal (prefix 0) formats.
One possible alternative is to pass a binary string to the parseInt method along with the radix:
var foo = parseInt('1111', 2); // foo will be set to 15
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How in node to split string by newline ('\n')?
How in node to split string by newline ('\n') ?
I have simple string like var a = "test.js\nagain.js" and I need to get ["test.js", "again.js"] .
I tried
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Difference between Statement and PreparedStatement
...name, email, birthdate, photo) VALUES (?, ?, ?, ?)");
preparedStatement.setString(1, person.getName());
preparedStatement.setString(2, person.getEmail());
preparedStatement.setTimestamp(3, new Timestamp(person.getBirthdate().getTime()));
preparedStatement.setBinaryStream(4, person.getPhoto());
prepa...
Get Substring between two characters using javascript
I am trying to extract a string from within a larger string where it get everything inbetween a ':' and a ';'.
16 Answers
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Getting the filenames of all files in a folder [duplicate]
...irectory, and then call the getName() method to get the filename.
List<String> results = new ArrayList<String>();
File[] files = new File("/path/to/the/directory").listFiles();
//If this pathname does not denote a directory, then listFiles() returns null.
for (File file : files) {
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Send email using java
...the message is not a MimeMessage
*/
public static void Send(final String username, final String password, String recipientEmail, String title, String message) throws AddressException, MessagingException {
GoogleMail.Send(username, password, recipientEmail, "", title, message);
}...