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Why are arrays covariant but generics are invariant?
From Effective Java by Joshua Bloch,
9 Answers
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Should the hash code of null always be zero, in .NET
...n.Spring;
Season? vnull = null;
if(vnull == v) // never TRUE
EDIT
From MSDN
If two objects compare as equal, the GetHashCode method for each object must return the same value. However, if two objects do not compare as equal, the GetHashCode methods for the two object do not have to return ...
Is HTML5 localStorage asynchronous?
... @TheMuffinMan: Your problem is probably related to nbf or exp from the auth token.
– Mendes
Nov 10 '17 at 13:10
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How to escape JSON string?
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For those using the very popular Json.Net project from Newtonsoft the task is trivial:
using Newtonsoft.Json;
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var s = JsonConvert.ToString(@"a\b");
Console.WriteLine(s);
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This code prints:
"a\\b"
That is, the resulting string value contains the quotes as well ...
Best way of invoking getter by reflection
...ersion (object to string, string to object) to simplify setting properties from user input.
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vs in Generics
...sn't covariant, even though logically it should work, since string derives from object. Before variance in generic interfaces was added to C# and VB.NET (in .NET 4 with VS 2010), this was a compile time error.
After .NET 4, IEnumerable<T> was marked covariant, and became IEnumerable<out T...
What's wrong with overridable method calls in constructors?
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On invoking overridable method from constructors
Simply put, this is wrong because it unnecessarily opens up possibilities to MANY bugs. When the @Override is invoked, the state of the object may be inconsistent and/or incomplete.
A quote from Effective ...
Setting up a JavaScript variable from Spring model by using Thymeleaf
I am using Thymeleaf as template engine. How I pass a variable from Spring model to JavaScript variable?
9 Answers
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Rails: Using build with a has_one association in rails
...w the top rated and accepted answer here is answering a different question from the one the OP asked.
– Ajedi32
Jun 27 '14 at 15:31
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Guid is all 0's (zeros)?
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Lessons to learn from this:
1) Guid is a value type, not a reference type.
2) Calling the default constructor new S() on any value type always gives you back the all-zero form of that value type, whatever it is. It is logically the same as...