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Python: fastest way to create a list of n lists
...y which is marginally faster than
d = [[] for x in xrange(n)]
is
from itertools import repeat
d = [[] for i in repeat(None, n)]
It does not have to create a new int object in every iteration and is about 15 % faster on my machine.
Edit: Using NumPy, you can avoid the Python loop using
d = n...
What's the difference between => , ()=>, and Unit=>
... is one of the many ways parameters can be passed. If you aren't familiar with them, I recommend taking some time to read that wikipedia article, even though nowadays it is mostly call-by-value and call-by-reference.
What it means is that what is passed is substituted for the value name inside the ...
Margin while printing html page
I am using a separate style-sheet for printing. Is it possible to set right and left margin in the style-sheet which set the print margin (i.e. margin on paper).
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Is there a function to deselect all text using JavaScript?
...here a function in javascript to just deselect all selected text? I figure it's got to be a simple global function like document.body.deselectAll(); or something.
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How to check if an email address exists without sending an email?
I have come across this PHP code to check email address using SMTP without sending an email .
14 Answers
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Disabled input text color
The simple HTML below displays differently in Firefox and WebKit-based browsers (I checked in Safari, Chrome and iPhone).
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How to specify an area name in an action link?
...g area. I see no overload for actionlink that takes an area parameter, is it possible to do?
9 Answers
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The most accurate way to check JS object's type?
...lass of an object:
Object.prototype.toString.call(t);
http://bonsaiden.github.com/JavaScript-Garden/#types
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Is it possible to rotate a drawable in the xml description?
I am creating an app, with resources that can be reused (because buttons are always the same, but mirrored or rotated). I do want to use the same resource so I don't have to add 3 more resources that are exactly like the original but rotated. But I also don't want to mix the code with things that ca...
Using context in a fragment
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You can use getActivity(), which returns the activity associated with a fragment.
The activity is a context (since Activity extends Context).
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