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What is the difference between re.search and re.match?
... @Alby match is much faster than search, so instead of doing regex.search("word") you can do regex.match((.*?)word(.*?)) and gain tons of performance if you are working with millions of samples.
– ivan_bilan
May 24 '16 at 9:34
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Regular expression to allow spaces between words
...bers. The regex below works great, but it doesn't allow for spaces between words.
15 Answers
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How to grep Git commit diffs or contents for a certain word?
In a Git code repository I want to list all commits that contain a certain word. I tried this
8 Answers
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How to move one word left in the vi editor
I use the shortcut w to move the cursor one word right. Is there a shortcut to move a word left?
5 Answers
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Soft hyphen in HTML ( vs. ­)
...e problem with soft hyphens on your web pages? In a text there can be long words which you might want to line break with a hyphen. But you do not want the hyphen to show if the whole word is on the same line.
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Dictionary text file [closed]
I am writing a program that needs A LOT of words of the English language. I am trying to find a dictionary file that has a lot of words. Does anyone know of a good source? I tried many sources but they don't seem to have it.
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Shorten string without cutting words in JavaScript
...s wondering how you would go about shortening a string without cutting any word off. I know how to use substring, but not indexOf or anything really well.
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UITextField auto-capitalization type - iPhone App
...utocapitalizationType for a UITextField so that the first letter of each word is capitalized by default?
7 Answers
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Double Iteration in List Comprehension
... to me! Suppose you have a text full of sentences and you want an array of words.
# Without list comprehension
list_of_words = []
for sentence in text:
for word in sentence:
list_of_words.append(word)
return list_of_words
I like to think of list comprehension as stretching code horizon...
Search for “does-not-contain” on a DataFrame in pandas
... and can't figure out how to filter a dataframe by df["col"].str.contains(word) , however I'm wondering if there is a way to do the reverse: filter a dataframe by that set's compliment. eg: to the effect of !(df["col"].str.contains(word)) .
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