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Add new methods to a resource controller in Laravel
...rameter like {id}? Currently I've coded my custom method inline in routes.php (like the example here laravel.com/docs/5.1/routing#route-parameters). Ideally I'd like to pass the parameter to run in FooController.
– ATutorMe
Jan 8 '16 at 7:13
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When and why I should use session_regenerate_id()?
Why and when should I use the session_regenerate_id() function in php?
Should I always use it after I use the session_start() ?
I've read that I have to use it to prevent session fixation, is this the only reason?
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Find the last element of an array while using a foreach loop in PHP
...t being said, you don't -have- to iterate over an "array" using foreach in php.
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Test if number is odd or even
...simplest most basic way to find out if a number/variable is odd or even in PHP?
Is it something to do with mod?
17 Answers
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In Laravel, the best way to pass different types of flash messages in the session
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Follow these steps below:
Create a file: "app/Components/FlashMessages.php"
namespace App\Components;
trait FlashMessages
{
protected static function message($level = 'info', $message = null)
{
if (session()->has('messages')) {
$messages = session()->pull('messages'...
Why is === faster than == in PHP?
Why is === faster than == in PHP?
11 Answers
11
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How do I get an object's unqualified (short) class name?
How do I check the class of an object within the PHP name spaced environment without specifying the full namespaced class.
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Get $_POST from multiple checkboxes
...ck_list'][]).
Here's a little sample as requested:
<form action="test.php" method="post">
<input type="checkbox" name="check_list[]" value="value 1">
<input type="checkbox" name="check_list[]" value="value 2">
<input type="checkbox" name="check_list[]" value="value...
JavaScript equivalent of PHP’s die
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I think that if PHP has a "firebug" equivalent, it should also write "1 error" on die() ;-) Good answer!
– Adrian Maire
Apr 25 '13 at 14:04
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jQuery pass more parameters into callback
.../ an object / whatever extra params you wish to pass.
$.post("someurl.php", someData, doSomething(extraStuff), "json");
};
What is happening?
In the last line, doSomething(extraStuff) is invoked and the result of that invocation is a function pointer.
Because extraStuff is passed as an argu...