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Removing duplicates from a list of lists
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>>> k = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4]]
>>> import itertools
>>> k.sort()
>>> list(k for k,_ in itertools.groupby(k))
[[1, 2], [3], [4], [5, 6, 2]]
itertools often offers the fastest and most powerf...
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Why does 2 mod 4 = 2?
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152
Mod just means you take the remainder after performing the division. Since 4 goes into 2 zero ti...
Extract elements of list at odd positions
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232
Solution
Yes, you can:
l = L[1::2]
And this is all. The result will contain the elements p...
Filter rows which contain a certain string
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263
The answer to the question was already posted by the @latemail in the comments above. You can ...
Shuffle two list at once with same order
...t pre-processing. But there is problem, in lists documents and documents2 I have the same documents and I need shuffle them in order to keep same order in both lists. I cannot shuffle them separately because each time I shuffle the list, I get other results. That is why I need to shuffle the at ...
Getting key with maximum value in dictionary?
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25 Answers
25
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How does zip(*[iter(s)]*n) work in Python?
...s to zip(), and it pulls an item from the iterator each time.
x = iter([1,2,3,4,5,6,7,8,9])
print zip(x, x, x)
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Concatenating two one-dimensional NumPy arrays
...separate arguments.
From the NumPy documentation:
numpy.concatenate((a1, a2, ...), axis=0)
Join a sequence of arrays together.
It was trying to interpret your b as the axis parameter, which is why it complained it couldn't convert it into a scalar.
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How to find the installed pandas version
...ion__:
In [76]: import pandas as pd
In [77]: pd.__version__
Out[77]: '0.12.0-933-g281dc4e'
Pandas also provides a utility function, pd.show_versions(), which reports the version of its dependencies as well:
In [53]: pd.show_versions(as_json=False)
INSTALLED VERSIONS
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commit: ...