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How do I make a matrix from a list of vectors in R?
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[8,] 8 1 2 3 4 5
[9,] 9 1 2 3 4 5
[10,] 10 1 2 3 4 5
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MySQL connection not working: 2002 No such file or directory
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answered Nov 4 '09 at 21:28
Alec GorgeAlec Gorge
15.3k99 gold badges5454 silver badges6969 bronze badges
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Are the shift operators () arithmetic or logical in C?
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Basically you need to either test your compiler or not rely on it. My VS2008 help for the current MS C++ compiler says that their compiler does an arithmetic shift.
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Detecting a mobile browser
...opera m(ob|in)i|palm( os)?|phone|p(ixi|re)\/|plucker|pocket|psp|series(4|6)0|symbian|treo|up\.(browser|link)|vodafone|wap|windows ce|xda|xiino/i.test(a)||/1207|6310|6590|3gso|4thp|50[1-6]i|770s|802s|a wa|abac|ac(er|oo|s\-)|ai(ko|rn)|al(av|ca|co)|amoi|an(ex|ny|yw)|aptu|ar(ch|go)|as(te|us)|attw|au(di|...
How exactly does the python any() function work?
... that lst is the iterable, which is a list of some items. If it contained [0, False, '', 0.0, [], {}, None] (which all have boolean values of False) then any(lst) would be False. If lst also contained any of the following [-1, True, "X", 0.00001] (all of which evaluate to True) then any(lst) would b...
Creating a CSS3 box-shadow on all sides but one
...paddings) and add shadow
#content {
font-size: 1.8em;
box-shadow: 0 0 8px 2px #888; /* line shadow */
}
add shadows to tabs:
#nav li a {
margin-left: 20px;
padding: .7em .5em .5em .5em;
font-size: 1.3em;
color: #FFF;
display: inline-block;
text-transform: uppercas...
stash@{1} is ambiguous?
I'm trying to get info about my stash, but git is telling me that stash@{0} and stash@{1} are ambiguous. git stash list works fine, and .git/logs/refs/stash seems to have the appropriate content (not that I'm an expert on git internals).
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Export database schema into SQL file
Is it possible in MS SQL Server 2008 to export database structure into a T-SQL file?
4 Answers
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How to break nested loops in JavaScript? [duplicate]
...o break to a label, like so:
function foo ()
{
dance:
for(var k = 0; k < 4; k++){
for(var m = 0; m < 4; m++){
if(m == 2){
break dance;
}
}
}
}
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How do I check the difference, in seconds, between two dates?
...tes, use total_seconds like this:
import datetime as dt
a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)
(b-a).total_seconds()
86400.0
#note that seconds doesn't give you what you want:
(b-a).seconds
0
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