大约有 48,000 项符合查询结果（耗时：0.0433秒） [XML]
Replace all elements of Python NumPy Array that are greater than some value
...o replace all values in it greater than or equal to a threshold T with 255.0. To my knowledge, the most fundamental way would be:
...
How to center absolute div horizontally using CSS?
...v and want it to be centered horizontally - although I'm giving it margin:0 auto; it's not centered...
8 Answers
...
How do I make a matrix from a list of vectors in R?
...
[8,] 8 1 2 3 4 5
[9,] 9 1 2 3 4 5
[10,] 10 1 2 3 4 5
share
|
improve this answer
|
follow
|
...
How to join absolute and relative urls?
...> import urlparse
>>> urlparse.urljoin(url1, url2)
'http://127.0.0.1/test1/test4/test6.xml'
With Python 3 (where urlparse is renamed to urllib.parse) you could use it as follow:
>>> import urllib.parse
>>> urllib.parse.urljoin(url1, url2)
'http://127.0.0.1/test1/test...
Python: Select subset from list based on index set
...
answered Jul 5 '10 at 11:32
kennytmkennytm
451k9292 gold badges980980 silver badges958958 bronze badges
...
Format JavaScript date as yyyy-mm-dd
I have a date with the format Sun May 11,2014 . How can I convert it to 2014-05-11 using JavaScript?
42 Answers
...
How to split a long regular expression into multiple lines in JavaScript?
... split into multiple lines in my JavaScript code to keep each line length 80 characters according to JSLint rules. It's just better for reading, I think.
Here's pattern sample:
...
How to get the separate digits of an int number?
I have numbers like 1100, 1002, 1022 etc. I would like to have the individual digits, for example for the first number 1100 I want to have 1, 1, 0, 0.
...
Zooming MKMapView to fit annotation pins?
...MKMapView and have added a number of annotation pins to the map about a 5-10 kilometre area. When I run the application my map starts zoomed out to show the whole world, what is the best way to zoom the map so the pins fit the view?
...
How do I check the difference, in seconds, between two dates?
...tes, use total_seconds like this:
import datetime as dt
a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)
(b-a).total_seconds()
86400.0
#note that seconds doesn't give you what you want:
(b-a).seconds
0
...