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Change the name of a key in dictionary
...
Easily done in 2 steps:
dictionary[new_key] = dictionary[old_key]
del dictionary[old_key]
Or in 1 step:
dictionary[new_key] = dictionary.pop(old_key)
which will raise KeyError if dictionary[old_key] is undefined. Note that this...
How does StartCoroutine / yield return pattern really work in Unity?
...oft referenced Unity3D coroutines in detail link is dead. Since it is mentioned in the comments and the answers I am going to post the contents of the article here. This content comes from this mirror.
Unity3D coroutines in detail
Many processes in games take place over the course of mult...
Reference one string from another string in strings.xml?
...d Sep 8 '17 at 19:22
Joseph Garrone
90899 silver badges1515 bronze badges
answered Oct 5 '16 at 9:29
Beeing Jk...
Best way to represent a fraction in Java?
...inal static BigFraction ZERO = new BigFraction(BigInteger.ZERO, BigInteger.ONE, true);
public final static BigFraction ONE = new BigFraction(BigInteger.ONE, BigInteger.ONE, true);
/**
* Constructs a BigFraction with given numerator and denominator. Fraction
* will be reduced to lowest te...
How do I use WPF bindings with RelativeSource?
...ource={RelativeSource TemplatedParent}}
or, shorter (this only works for OneWay bindings):
{TemplateBinding Path=PathToProperty}
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Python “extend” for a dictionary
What is the best way to extend a dictionary with another one while avoiding the use of a for loop? For instance:
7 Answer...
Error Code: 1005. Can't create table '…' (errno: 150)
...is problem on the Internet and checked the Stack Overflow questions, but none of the solutions worked for my case.
13 Answ...
`static` keyword inside function?
...
Seems like nobody mentioned so far, that static variables inside different instances of the same class remain their state. So be careful when writing OOP code.
Consider this:
class Foo
{
public function call()
{
static $test = 0;
...
One line if statement not working
... value. There is no need for the conditional operator to even exist, let alone use it.
BTW: it is customary to name methods which are used to ask a question with a question mark at the end, like this:
@item.rigged?
This shows another problem with using the conditional operator in Ruby:
@item.ri...
What are the implications of using “!important” in CSS? [duplicate]
...t's never okay to use though.
What's wrong with !important:
Specificity is one of the main forces at work when the browser decides how CSS affects the page. The more specific a selector is, the more importance is added to it. This usually coincides with how often the selected element occurs. For exa...
