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How can I make pandas dataframe column headers all lowercase?
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You can do it like this:
data.columns = map(str.lower, data.columns)
or
data.columns = [x.lower() for x in data.columns]
example:
>>> data = pd.DataFrame({'A':range(3), 'B':range(3,0,-1), 'C':list('abc')})
>>>...
How to reset Django admin password?
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python manage.py changepassword <user_name>
see docs
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Detect when browser receives file download
I have a page that allows the user to download a dynamically-generated file. It takes a long time to generate, so I'd like to show a "waiting" indicator. The problem is, I can't figure out how to detect when the browser has received the file, so I can hide the indicator.
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Is there a way to disable the Title and Subtitle in Highcharts?
I'm just going to hardcode it in using html that is around the graph, I don't want to use the built in.
14 Answers
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Are the PUT, DELETE, HEAD, etc methods available in most web browsers?
...d Oct 3 '08 at 12:02
Matthew MurdochMatthew Murdoch
28.1k2525 gold badges8686 silver badges124124 bronze badges
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PowerShell equivalent to grep -f
...'m looking for the PowerShell equivalent to grep --file=filename . If you don't know grep , filename is a text file where each line has a regular expression pattern you want to match.
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Create new user in MySQL and give it full access to one database
...ommand like create database dbTest; . What would be the MySQL commands to do that?
8 Answers
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Best way to merge two maps and sum the values of same key?
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Scalaz has the concept of a Semigroup which captures what you want to do here, and leads to arguably the shortest/cleanest solution:
scala> import scalaz._
import scalaz._
scala> import Scalaz._
import Scalaz._
scala> val map1 = Map(1 -> 9 , 2 -> 20)
map1: scala.collection.imm...
Scroll back to the top of scrollable div
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var myDiv = document.getElementById('containerDiv');
myDiv.innerHTML = variableLongText;
myDiv.scrollTop = 0;
See the scrollTop attribute.
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Changing a specific column name in pandas DataFrame
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A one liner does exist:
In [27]: df=df.rename(columns = {'two':'new_name'})
In [28]: df
Out[28]:
one three new_name
0 1 a 9
1 2 b 8
2 3 c 7
3 4 d 6
4 5 e 5
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