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Circle drawing with SVG's arc path
...e best solution. Still need to handle the 100% case, but just by "rounding down" to 99.999% rather than with a whole separate code branch.
– SimonR
Apr 18 '16 at 14:03
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gulp globbing- how to watch everything below directory
...uestion, but I haven't really been able to find a satisfactory answer: How do I use gulp globbing to select all files in all subdirectories below a certain directory?
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How to reset Django admin password?
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python manage.py changepassword <user_name>
see docs
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Bootstrap 3 Navbar Collapse
...ch the bootstrap 3 navbar collapses (i.e. so that it collapses into a drop down on portrait tablets)?
12 Answers
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Downloading a Google font and setting up an offline site that uses it
...oogle.com/fonts/ , add the font you like to your collection, and press the download button. And then just use the @fontface to connect this font to your web page.
Btw, if you open the link you are using, you'll see an example of using @fontface
http://fonts.googleapis.com/css?family=Open+Sans:400...
Is there a way to disable the Title and Subtitle in Highcharts?
I'm just going to hardcode it in using html that is around the graph, I don't want to use the built in.
14 Answers
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PowerShell equivalent to grep -f
...'m looking for the PowerShell equivalent to grep --file=filename . If you don't know grep , filename is a text file where each line has a regular expression pattern you want to match.
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Invalidating JSON Web Tokens
...de further ones.
1) Simply remove the token from the client
Obviously this does nothing for server side security, but it does stop an attacker by removing the token from existence (ie. they would have to have stolen the token prior to logout).
2) Create a token blocklist
You could store the invalid ...
Scroll back to the top of scrollable div
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var myDiv = document.getElementById('containerDiv');
myDiv.innerHTML = variableLongText;
myDiv.scrollTop = 0;
See the scrollTop attribute.
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Changing a specific column name in pandas DataFrame
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A one liner does exist:
In [27]: df=df.rename(columns = {'two':'new_name'})
In [28]: df
Out[28]:
one three new_name
0 1 a 9
1 2 b 8
2 3 c 7
3 4 d 6
4 5 e 5
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