大约有 44,000 项符合查询结果（耗时：0.0620秒） [XML]
For files in directory, only echo filename (no path)
.../}"
done
The above uses Parameter Expansion which is native to the shell and does not require a call to an external binary such as basename
However, might I suggest just using find
find /home/user -type f -printf "%f\n"
...
Why should a function have only one exit-point? [closed]
...ngle exit-point function as a bad way to code because you lose readability and efficiency. I've never heard anybody argue the other side.
...
Is it possible to register a http+domain-based URL Scheme for iPhone apps, like YouTube and Maps?
...://martijnthe.nl ) with my app whenever the app is installed on the phone, and with Mobile Safari in case it is not.
13 Ans...
Using fonts with Rails asset pipeline
...
If your Rails version is between > 3.1.0 and < 4, place your fonts in any of the these folders:
app/assets/fonts
lib/assets/fonts
vendor/assets/fonts
For Rails versions > 4, you must place your fonts in the app/assets/fonts folder.
Note: To place fonts...
Rails: How to get the model class name based on the controller class name?
...
If your controller and model are in the same namespace, then what you want is
controller_path.classify
controller_path gives you the namespace; controller_name doesn't.
For example, if your controller is
Admin::RolesController
then:
con...
How to get the path of a running JAR file?
My code runs inside a JAR file, say foo.jar , and I need to know, in the code, in which folder the running foo.jar is.
3...
What is the difference between synchronous and asynchronous programming (in node.js)
I've been reading nodebeginner
And I came across the following two pieces of code.
10 Answers
...
DataContractSerializer doesn't call my constructor?
...y will leak! 2) You are initializing the object twice, once in constructor and once by the deserialized values.
– Dudu
Feb 13 '11 at 3:02
...
What does the explicit keyword mean?
...hat takes a Foo object:
void DoBar (Foo foo)
{
int i = foo.GetFoo ();
}
and here's where the DoBar function is called:
int main ()
{
DoBar (42);
}
The argument is not a Foo object, but an int. However, there exists a constructor for Foo that takes an int so this constructor can be used to conv...
Upgrade python in a virtualenv
...
Did you see this? If I haven't misunderstand that answer, you may try to create a new virtualenv on top of the old one. You just need to know which python is going to use your virtualenv (you will need to see your virtualenv version).
If your virtualenv is install...