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Visual Studio 2013 Update 4【VS2013 SP4 旗舰版下载地址】 - 其他 - 清泛...

..._update_4_x86_dvd_5935081.iso 语言: Chinese - Simplified SHA1:5F924E3B8F6715F92DCD2F8E58558833D310A146 http://download.microsoft.com/do ... s2013.4_ult_chs.iso Visual Studio Ultimate 2013 with Update 4 (x86) - DVD (English):7108 MB 发布日期: 2014/11/12 文件名: en_visual_st...
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HC-05 蓝牙模块开发 - 创客硬件开发 - 清泛IT社区,为创新赋能!

... 2、默认是GBK编码,非UTF-8的,如“你好”对应16进制:C4 E3 BA C3。而AI2中文字符串默认是UTF-8编码的(E4 BD A0 E5 A5 BD )。 如果遇到 Error 507 错误: 极有可能是硬件问题:
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App Inventor 2 经典蓝牙(SPP) 硬件接入:hc05 · App Inventor 2 中文网

... 2、默认是GBK编码,非UTF-8的,如“你好”对应16进制:C4 E3 BA C3。而AI2中文字符串默认是UTF-8编码的(E4 BD A0 E5 A5 BD )。 参与讨论 如有问题,社区点此回帖参与讨论。 您的改进建议 ...
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Removing MySQL 5.7 Completely [closed]

... answered Oct 10 '12 at 13:06 E3GE3G 44955 silver badges55 bronze badges ...
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二维码的生成细节及原理 - 更多技术 - 清泛网 - 专注C/C++及内核技术

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Is there a difference between “==” and “is”?

...0**3 evaluates to True in Python 3.7 since 10**3 is type int. But 1000 is 1e3 evaluates to False since 1e3 is type float. – Ahmed Fasih Sep 8 '19 at 1:13 ...
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Why does changing the sum order returns a different result?

... output is as follows: 403787ae147ae148: 23.53 4017851eb851eb85: 5.88 4031a3d70a3d70a4: 17.64 4047866666666666: 47.05 -------- 403d68f5c28f5c29: 29.41 4047866666666666: 47.05 -------- 404495c28f5c28f6: 41.17 4047866666666667: 47.050000000000004 The first 4 numbers are x, y, z, and s's hexadecimal...
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Applicatives compose, monads don't

... If you have applicatives A1 and A2, then the type data A3 a = A3 (A1 (A2 a)) is also applicative (you can write such an instance in a generic way). On the other hand, if you have monads M1 and M2 then the type data M3 a = M3 (M1 (M2 a)) is not necessarily a monad (there is no se...
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How does this milw0rm heap spraying exploit work?

... xchg eax,esp 00000039 E99AA4D58D jmp 0x8dd5a4d8 0000003E E5A3 in eax,0xa3 00000040 1F pop ds 00000041 4C dec esp 00000042 EB46 jmp short 0x8a 00000044 4B dec ebx 00000045 8CD0 mov eax,ss 00000047...
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How to create GUID / UUID?

...ardry I can't take credit for: function uuidv4() { return ([1e7]+-1e3+-4e3+-8e3+-1e11).replace(/[018]/g, c => (c ^ crypto.getRandomValues(new Uint8Array(1))[0] & 15 >> c / 4).toString(16) ); } console.log(uuidv4()); Update, 2020-01-06: There is a proposal in t...