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使用虚拟现实和App Inventor进行实验 · App Inventor 2 中文网

... 教育 入门必读 中文教程 IoT专题 AI2拓展 ChatGPT接入 Aia Store 开通VIP 搜索 使用虚拟现实和App Inventor进行实...
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Is ASCII code 7-bit or 8-bit?

My teacher told me ASCII is 8-bit character coding scheme. But it is defined only for 0-127 codes which means it can be fit into 7-bits. So can't it be argued that ASCII bit is actually 7-bit code? ...
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GestureDetect 手势检测扩展:识别滑动、点击和长按手势 · App Inventor 2 中文网

...将布局组件绑定到扩展即可使用 非可视组件:不会占用界面空间 事件驱动:通过事件处理各种手势操作 兼容性强:适用于各种布局组件 支持的手势 向上滑动 (Swipe Up) 向下滑动 (Swipe Down) 向左滑动 (...
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pypi UserWarning: Unknown distribution option: 'install_requires'

...ed Nov 28 '11 at 15:38 Fredrik HåårdFredrik Håård 2,4622020 silver badges3232 bronze badges ...
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Get random item from array [duplicate]

...swered Dec 23 '13 at 10:54 Naâmèn Mohamed AmineNaâmèn Mohamed Amine 18911 silver badge33 bronze badges ...
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App Inventor 2 UrsPahoMqttClient 拓展 - 物联网轻量级MQTT协议 · App Inventor 2 中文网

...数 要连接到MQTT消息服务器,组件需要设置连接选项,“界面设计”或“程序设计”视图均可进行设置。 连接信息 Broker - MQTT消息服务器 服务器的主机名或 IP 地址。 Port - 端口 连接的端口号。默认值为 1883。 Protocol - ...
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vc第三方界面库BCGControlBar与Xtreme Toolkit对比 - C/C++ - 清泛网 - 专注C/C++及内核技术

vc第三方界面库BCGControlBar与Xtreme Toolkit对比原文来自http: www.webui8.com xinwen 557vc第三方界面库BCGControlBar与Xtreme Toolkit对比BCGControlBar简介BCGControlBar专业版(BCGCo...原文来自:http://www.webui8.com/xinwen/557 BCGControlBar简介 BCGControlBar专业版...
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Duilib非常强大的C++界面库 - C/C++ - 清泛网 - 专注C/C++及内核技术

Duilib非常强大的C++界面库Duilib 是一款强大的界面开发工具,可以将用户界面和处理逻辑彻底分离,极大地提高用户界面的开发效率。Duilib 是国内首个开源 的direct Duilib 是一款强大的界面开发工具,可以将用户界面和处理逻辑...
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Coding in Other (Spoken) Languages

...nnish names, there's a similar dilemma about whether to use special chars (äöå) or replace them with a & o (and if you do use them, you're likely running into charset problems). But yeah, fortunately I haven't had to use Finnish in code for at least 7 years. :) – Jonik ...
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Extract subset of key-value pairs from Python dictionary object?

...works in 2.7 too): {k: bigdict[k] for k in ('l', 'm', 'n')} Update: As Håvard S points out, I'm assuming that you know the keys are going to be in the dictionary - see his answer if you aren't able to make that assumption. Alternatively, as timbo points out in the comments, if you want a key tha...