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What are the “standard unambiguous date” formats for string-to-date conversion in R?
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answered Feb 7 '13 at 16:10
Joshua UlrichJoshua Ulrich
157k2929 gold badges308308 silver badges388388 bronze badges
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Creating Threads in python
...e__ == "__main__":
thread = Thread(target = threaded_function, args = (10, ))
thread.start()
thread.join()
print("thread finished...exiting")
Here I show how to use the threading module to create a thread which invokes a normal function as its target. You can see how I can pass wh...
Converting NSString to NSDate (and back again)
How would I convert an NSString like " 01/02/10 " (meaning 1st February 2010) into an NSDate ? And how could I turn the NSDate back into a string?
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How do I perform the SQL Join equivalent in MongoDB?
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310
As of Mongo 3.2 the answers to this question are mostly no longer correct. The new $lookup oper...
What Process is using all of my disk IO
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edited Sep 1 '17 at 10:11
sjas
14.6k1111 gold badges7171 silver badges7575 bronze badges
answered ...
Django: How to manage development and production settings?
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110
The DJANGO_SETTINGS_MODULE environment variable controls which settings file Django will load. ...
What does the restrict keyword mean in C++?
...d, here's a link to the audio from his GDC presentation. gdcvault.com/play/1022689/Memory
– Grimeh
Dec 8 '16 at 20:21
1
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Converting Long to Date in Java returns 1970
... the time as long in milliseconds, not seconds. You need to multiply it by 1000 and make sure that you supply it as long.
Date d = new Date(1220227200L * 1000);
This shows here
Sun Aug 31 20:00:00 GMT-04:00 2008
shar...
How to do date/time comparison
...e(end)
}
func main() {
start, _ := time.Parse(time.RFC822, "01 Jan 15 10:00 UTC")
end, _ := time.Parse(time.RFC822, "01 Jan 16 10:00 UTC")
in, _ := time.Parse(time.RFC822, "01 Jan 15 20:00 UTC")
out, _ := time.Parse(time.RFC822, "01 Jan 17 10:00 UTC")
if inTimeSpan(start, end,...
Flattening a shallow list in Python [duplicate]
...company.
>>> list_of_menuitems = [['image00', 'image01'], ['image10'], []]
>>> import itertools
>>> chain = itertools.chain(*list_of_menuitems)
>>> print(list(chain))
['image00', 'image01', 'image10']
It will work on anything that's iterable, which should inclu...