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What would cause an algorithm to have O(log log n) complexity?
...= 8,192
8,192 / 2 = 4,096
4,096 / 2 = 2,048
2,048 / 2 = 1,024
1,024 / 2 = 512
512 / 2 = 256
256 / 2 = 128
128 / 2 = 64
64 / 2 = 32
32 / 2 = 16
16 / 2 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
This process takes 16 steps, and it's also the case that 65,536 = 216.
But, if we take the square root at each leve...
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edited May 10 '12 at 11:47
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edited Oct 12 '18 at 11:54
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Sep 25 '12 at 23:57
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...plicitly stringified) in the object we stringify. See: stackoverflow.com/a/12659424/2044940
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