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How to pass variable number of arguments to a PHP function

...u can pack your parameters into an array, like this : $params = array( 10, 'glop', 'test', ); And, then, call the function : call_user_func_array('test', $params); This code will the output : int 3 array 0 => int 10 1 => string 'glop' (length=4) 2 => string 'test' (lengt...
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Handling a colon in an element ID in a CSS selector [duplicate]

... answered Sep 23 '08 at 16:52 Mark CidadeMark Cidade 92k3131 gold badges215215 silver badges229229 bronze badges ...
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How can I make a WPF combo box have the width of its widest element in XAML?

... answered Jun 24 '09 at 16:02 micahtanmicahtan 15.5k11 gold badge3434 silver badges3333 bronze badges ...
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Create a GUID in Java

...il Bourque 186k5757 gold badges571571 silver badges804804 bronze badges answered Jun 6 '10 at 1:14 Mark ByersMark Byers 683k155155...
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About catching ANY exception

... int(s.strip()) except IOError as (errno, strerror): print "I/O error({0}): {1}".format(errno, strerror) except ValueError: print "Could not convert data to an integer." except: print "Unexpected error:", sys.exc_info()[0] raise ...
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Mockito: Trying to spy on method is calling the original method

I'm using Mockito 1.9.0. I want mock the behaviour for a single method of a class in a JUnit test, so I have 9 Answers ...
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Replace Fragment inside a ViewPager

...s needs to be aware of which fragment that should be displayed in position 0, FirstPageFragment or NextFragment. One way of doing this is supplying a listener when creating FirstPageFragment, which will be called when it is time to switch fragments. I think this is a good thing though, to let your f...
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Could not load file or assembly 'System.Data.SQLite'

... | edited Aug 27 '09 at 14:00 answered Aug 15 '09 at 13:27 ...
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What are namespaces?

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Declaring array of objects

... sample.push(new Object()); To do this n times use a for loop. var n = 100; var sample = new Array(); for (var i = 0; i < n; i++) sample.push(new Object()); Note that you can also substitute new Array() with [] and new Object() with {} so it becomes: var n = 100; var sample = []; for ...