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How to split a sequence into two pieces by predicate?
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By using partition method:
scala> List(1,2,3,4).partition(x => x % 2 == 0)
res0: (List[Int], List[Int]) = (List(2, 4),List(1, 3))
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`elif` in list comprehension conditionals
...ere designed exactly for this sort of use-case:
>>> l = [1, 2, 3, 4, 5]
>>> ['yes' if v == 1 else 'no' if v == 2 else 'idle' for v in l]
['yes', 'no', 'idle', 'idle', 'idle']
Hope this helps :-)
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Regular expression search replace in Sublime Text 2
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edited Nov 19 '19 at 14:08
answered Aug 5 '12 at 20:41
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Reverse Range in Swift
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Update For latest Swift 3 (still works in Swift 4)
You can use the reversed() method on a range
for i in (1...5).reversed() { print(i) } // 5 4 3 2 1
Or stride(from:through:by:) method
for i in stride(from:5,through:1,by:-1) { print(i) } // 5 4 3 2 1
stide(from:to:b...
New Array from Index Range Swift
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edited Jan 28 '15 at 17:24
answered Jun 4 '14 at 10:01
Cez...
how to set “camera position” for 3d plots using python/matplotlib?
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164
By "camera position," it sounds like you want to adjust the elevation and the azimuth angle that...
How to swap keys and values in a hash
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edited Jan 14 at 0:20
the Tin Man
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Best way to find the intersection of multiple sets?
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465
From Python version 2.6 on you can use multiple arguments to set.intersection(), like
u = set...