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How to get access to HTTP header information in Spring MVC REST controller?
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Prefer abstractions to the low-level details of an API. I would much rather have Spring MVC abstract away the details of the Servlet API. I can use the annotations to pull what I need out of the request.
– Vidya
Oct 24 '13 at 14:50
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A Java API to generate Java source files [closed]
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Sun provides an API called CodeModel for generating Java source files using an API. It's not the easiest thing to get information on, but it's there and it works extremely well.
The easiest way to get hold of it is as part of the JAXB 2 RI...
Embedded MongoDB when running integration tests
... Just used this library and it worked perfectly JUnit testing a Mongo API on a Mac. Recommended.
– Martin Dow
Jun 8 '12 at 13:38
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Should I use PATCH or PUT in my REST API?
...trick to remember the importance of Resources in REST).
About PUT /groups/api/v1/groups/{group id}/status/activate: you are not updating an "activate". An "activate" is not a thing, it's a verb. Verbs are never good resources. A rule of thumb: if the action, a verb, is in the URL, it probably is no...
How to change progress bar's progress color in Android
...IndeterminateDrawable() instead of getProgressDrawable().
Since Lollipop (API 21) you can set a progress tint:
progressBar.setProgressTintList(ColorStateList.valueOf(Color.RED));
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improv...
opengl: glFlush() vs. glFinish()
...s left, and the results should be available too all appropriate non-OpenGL APIs (e.g. reads from the framebuffer, screenshots, etc...). Whether that is really what happens is driver-dependent. The specification allows a ton of latitude as to what is legal.
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Finish all previous activities
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The proper solution, but only API 11+
– riwnodennyk
Jan 13 '14 at 17:16
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How do I configure IIS for URL Rewriting an AngularJS application in HTML5 mode?
... negate="true" />
<add input="{REQUEST_URI}" pattern="^/(api)" negate="true" />
</conditions>
<action type="Rewrite" url="/" />
</rule>
</rules>
</rewrite>
</system.webServer>
In my index.html I added ...
How do I read / convert an InputStream into a String in Java?
...limiter("\\A");
String result = s.hasNext() ? s.next() : "";
Using Stream API (Java 8). Warning: This solution converts different line breaks (like \r\n) to \n.
String result = new BufferedReader(new InputStreamReader(inputStream))
.lines().collect(Collectors.joining("\n"));
Using parallel Stre...
How to completely remove an issue from GitHub?
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No, the github API only allows you to open/close/reopen issues. Here's the Issues API docs.
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