大约有 35,487 项符合查询结果(耗时:0.0422秒) [XML]
How to resume Fragment from BackStack if exists
...;
boolean fragmentPopped = manager.popBackStackImmediate (backStateName, 0);
if (!fragmentPopped){ //fragment not in back stack, create it.
FragmentTransaction ft = manager.beginTransaction();
ft.replace(R.id.content_frame, fragment);
ft.addToBackStack(backStateName);
ft.commit(...
How can I output a UTF-8 CSV in PHP that Excel will read properly?
...
30 Answers
30
Active
...
Base64Util 拓展:支持图像框、画布、文件、文本字符串、图像精灵base64编...
...系方式: 不需要回复的可留空~ 意见反馈(300字以内): 给个鼓励也行呐~o~ 提供截图(仅截取当前可视区域) delete edit 高亮或隐藏信息 ...
Are there strongly-typed collections in Objective-C?
...<NSString*>* arr = @[@"str"];
NSString* string = [arr objectAtIndex:0];
NSNumber* number = [arr objectAtIndex:0]; // Warning: Incompatible pointer types initializing 'NSNumber *' with an expression of type 'NSString *'
And in Swift code, they will produce a compiler error:
var str: String ...
How to create a bash script to check the SSH connection?
...h -q user@downhost exit
$ echo $?
255
$ ssh -q user@uphost exit
$ echo $?
0
EDIT: Another approach would be to use nmap (you won't need to have keys or login-stuff):
$ a=`nmap uphost -PN -p ssh | grep open`
$ b=`nmap downhost -PN -p ssh | grep open`
$ echo $a
22/tcp open ssh
$ echo $b
(empty st...
Safely turning a JSON string into an object
...
1990
JSON.parse(jsonString) is a pure JavaScript approach so long as you can guarantee a reasonably m...
Delete files older than 3 months old in a directory using .NET
...
answered Feb 8 '10 at 14:57
Steve DannerSteve Danner
20.3k77 gold badges3333 silver badges4848 bronze badges
...
How to reverse a string in Go?
...e.
func Reverse(s string) string {
runes := []rune(s)
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
runes[i], runes[j] = runes[j], runes[i]
}
return string(runes)
}
share
|
...
Counting the occurrences / frequency of array elements
...oo(arr) {
var a = [], b = [], prev;
arr.sort();
for ( var i = 0; i < arr.length; i++ ) {
if ( arr[i] !== prev ) {
a.push(arr[i]);
b.push(1);
} else {
b[b.length-1]++;
}
prev = arr[i];
}
return [a, b];
}
Li...
