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Should each and every table have a primary key?
... thinking I wouldn't need one, I've ended up going back and adding one. I now create even my join tables with an auto-generated identity field that I use as the primary key.
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Browser detection in JavaScript? [duplicate]
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Would be nice to know all the results this function returns...
– Diego
Jan 27 '14 at 17:12
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Why catch and rethrow an exception in C#?
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@Fredrick, just fyi (though you probably know) if you're not going to use that ex object, then there's no need to instantiate it.
– Eoin Campbell
May 19 '09 at 8:16
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java.lang.UnsupportedClassVersionError Unsupported major.minor version 51.0 [duplicate]
... select Compiler Compliance Level to 1.6 or 1.5, build and test your app.
Now, it should be fine.
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Save ArrayList to SharedPreferences
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I'm sorry, I don't have an Android SDK to test it now, but take a look here: benjii.me/2010/04/deserializing-json-in-android-using-gson . You should iterate over the json array and do what they do there for each object, hopefully I'll be able to post an edit to my answer wit...
Get epoch for a specific date using Javascript
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You can also use Date.now() function.
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sql primary key and index
...ate your own alternate index on that column, then drop the default index.
Now for the fun part--when do you NOT want a unique primary key index? You don't want one, and can't tolerate one, when your table acquires enough data (rows) to make the maintenance of the index too expensive. This varies ...
Regex - Does not contain certain Characters
...special characters: the shell interprets some of them. Look to see if you now have a file named ']+$' in your directory. Put the entire regex inside single quotes to make it work.
– Ned Batchelder
Sep 11 '17 at 23:50
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How do you add Boost libraries in CMakeLists.txt?
... can also use FIND_PACKAGE(Boost REQUIRED COMPONENTS system) if you don't know the exact version of boost to use
– smac89
Aug 17 '17 at 6:39
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Importing data from a JSON file into R
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x$user$name, x$user$user_id should now be x$user['name'], x$user['user_id']. Also, m <- do.call(rbind, m) might be a better way of converting the list to a matrix.
– jbaums
Oct 10 '13 at 1:16
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