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How to pass arguments from command line to gradle
...:
task(runProgram, type: JavaExec) {
[...]
if (project.hasProperty('myargs')) {
args(myargs.split(','))
}
... and run at the command line like this
% ./gradlew runProgram '-Pmyargs=-x,7,--no-kidding,/Users/rogers/tests/file.txt'
...
How to remove focus without setting focus to another control?
I like my UIs to be intuitive; each screen should naturally and unobtrusively guide the user on to the next step in the app. Barring that, I strive to make things as confusing and confounding as possible.
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Android Eclipse - Could not find *.apk
...of solutions out there, yet none seem to work for me. I was able to build my apk without issues until this error started cropping up. I have tried cleaning my project, removing it from the workspace and reimporting it, removing "Java Builder" from my Builders for the project, building the project ...
Link latest file on Bitbucket Git repository
...y idea how to that for private repo? When I click on raw url of a image in my private repo, it redirects to bytebucket.org & append a token so that it can be viewed publicly...like https://bytebucket.org/$username/$repo/raw/$sha/$filename.jpg?token=$sometoken. But the token is different for each...
Android Fragment no view found for ID?
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This was exactly my problem, thank you. Odd though, this only occurred in landscape orientation when calling .show(). Using it to replace the main fragment worked fine.
– cohenadair
Sep 7 '15 at 20:05
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How to create new tmux session if none exists
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When this creates a new session, the default path is my home directory, not the path from which tmux was invoked.
– Richard Hansen
Sep 14 '11 at 22:31
2
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Configure Flask dev server to be visible across the network
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how to access the flask script globally, hosting on my own server
– pyd
Jul 12 '18 at 10:37
Thi...
MySQL Database won't start in XAMPP Manager-osx
...st fine. Today I installed a voice recognition software and then restarted my computer. Ever since, MySQL won't start in my manager-osx application. It doesn't throw me an in the application log. This is what it says:
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JQuery: 'Uncaught TypeError: Illegal invocation' at ajax request - several elements
...nt instead of its value, which is actually what I wanted to do (in fact in my php code I need that value as a foreign key for querying my cities table and filter correct entries).
So, instead of:
var data = {
'mode': 'filter_city',
'id_A': e[e.selectedIndex]
};
it should be:
var...
“The file ”MyApp.app“ couldn't be opened because you don't have permission to view it” when running
Whenever I try to run my app in Xcode 6 Beta 4 I am getting the error:
57 Answers
57
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