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Makefile经典教程（入门必备） - C/C++ - 清泛网移动版 - 专注C++内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
Makefile经典教程（入门必备） - C/C++ - 清泛网移动版 - 专注C++内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
Makefile经典教程（入门必备） - C/C++ - 清泛网移动版 - 专注C++内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C/C++及内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C/C++及内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
What's the correct way to communicate between controllers in AngularJS?
...
Edit: The issue addressed in this answer have been resolved in angular.js version 1.2.7. $broadcast now avoids bubbling over unregistered scopes and runs just as fast as $emit.
So, now you can:
use $broadcast from the $rootScope
listen using $on from the local $scope that needs to kno...
Makefile经典教程（入门必备） - C/C++ - 清泛网移动版 - 专注C/C++及内核技术
...ariable-name>同样可以是一个函数的返回值。注意，ifdef只是测试一个变量是否有值，其并不会把变量扩展到当前位置。还是来看两个例子：
示例一：
bar =
foo = $(bar)
ifdef foo
frobozz = yes
else
frobozz = no
endif
示例...
Android ClickableSpan not calling onClick
I am creating a ClickableSpan, and it is displaying properly with
the proper text underlined. However, the clicks are not registering.
Do you know what I am doing wrong???
...
How to find out which processes are using swap space in Linux?
Under Linux, how do I find out which process is using the swap space more?
17 Answers
...
Merge 2 arrays of objects
...rray.prototype.push.apply(arr1,arr2);
For Example
var arr1 = [{name: "lang", value: "English"},{name: "age", value: "18"}];
var arr2 = [{name : "childs", value: '5'}, {name: "lang", value: "German"}];
Array.prototype.push.apply(arr1,arr2);
console.log(arr1); // final merged result will be in ...