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Javascript reduce() on Object

...} } const total = Object.values(add).reduce((t, {value}) => t + value, 0) console.log(total) // 6 or simply: const add = { a: 1, b: 2, c: 3 } const total = Object.values(add).reduce((t, n) => t + n) console.log(total) // 6 ...
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Diff Algorithm? [closed]

... answered Aug 21 '09 at 17:23 jscharfjscharf 5,27022 gold badges1919 silver badges1515 bronze badges ...
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Show Youtube video source into HTML5 video tag?

...irplay="allow" data-youtube-id="N9oxmRT2YWw" src="http://v20.lscache8.c.youtube.com/videoplayback?sparams=id%2Cexpire%2Cip%2Cipbits%2Citag%2Cratebypass%2Coc%3AU0hPRVRMVV9FSkNOOV9MRllD&itag=43&ipbits=0&signature=D2BCBE2F115E68C5FF97673F1D797F3C3E3BFB99.59252109...
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Dynamically load JS inside JS [duplicate]

... kayenkayen 4,27033 gold badges1616 silver badges2020 bronze badges ...
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passport.js RESTful auth

... +50 There are many questions asked here, and it seems that even though the questions are asked in the context of Node and passport.js the ...
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How to filter multiple values (OR operation) in angularJS

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How does the bitwise complement operator (~ tilde) work?

...ple, here's the representation of -2 in two's complement: (8 bits) 1111 1110 The way you get this is by taking the binary representation of a number, taking its complement (inverting all the bits) and adding one. Two starts as 0000 0010, and by inverting the bits we get 1111 1101. Adding one gets u...
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For every character in string

...fashioned for-loop: std::string str = ???; for(std::string::size_type i = 0; i < str.size(); ++i) { do_things_with(str[i]); } Looping through the characters of a null-terminated character array: char* str = ???; for(char* it = str; *it; ++it) { do_things_with(*it); } ...
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WinDbg基础资料(日本語) - IT优秀资料 - 清泛网 - 专注C/C++及内核技术

... ③ Get Call Stack (Signal Thread) k kv kd (Multi Thread) ~* k ~0s Set Current Thread,0はThread No.である、変数 ④引き続き実行 (Signal Thread) g (Multi Thread) ~* g ⑤Get .Net Call Stack .load C:\Windows\Microsoft.NET\Framework\v2.0.50727\SOS.dll .l...
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MySQL - Using COUNT(*) in the WHERE clause

... try this; select gid from `gd` group by gid having count(*) > 10 order by lastupdated desc share | improve this answer | follow | ...