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Python time measure function
...et = f(*args)
time2 = time.time()
print '%s function took %0.3f ms' % (f.func_name, (time2-time1)*1000.0)
return ret
return wrap
And the usage is very simple, just use the @timing decorator:
@timing
def do_work():
#code
Python 3:
def timing(f):
def wrap(*args, **k...
MySQL - Using COUNT(*) in the WHERE clause
...
try this;
select gid
from `gd`
group by gid
having count(*) > 10
order by lastupdated desc
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Fastest way to tell if two files have the same contents in Unix/Linux?
...
410
I believe cmp will stop at the first byte difference:
cmp --silent $old $new || echo "files are...
FAT32系统中长文件名的存储 - C/C++ - 清泛网 - 专注C/C++及内核技术
...表示定义
字节偏移(16进制)
字节数
定义
0x0~0x7
8
文件名
0x8~0xA
3
扩展名
0xB*
1
属性字节
00000000(读写)
00000001(只读)
00000010(隐藏)
00000100(系统)
00001000(卷标)
00010000(...
Input placeholders for Internet Explorer
...Length="6" type="text" placeholder="Hi Mom">
<label style="font: 0.75em/normal sans-serif; left: 5px; top: 3px; width: 147px; height: 15px; color: rgb(186, 186, 186); position: absolute; overflow-x: hidden; font-size-adjust: none; font-stretch: normal;" for="placeholder1314588474481">Hi...
In mocha testing while calling asynchronous function how to avoid the timeout Error: timeout of 2000
...nous functions using mocha, I'm getting timeout error ( Error: timeout of 2000ms exceeded. ). How can I resolve this?
7 Ans...
Listing all permutations of a string/integer
...more elaborate (and since it is tagged c #), from http://radio.weblogs.com/0111551/stories/2002/10/14/permutations.html :
Rather lengthy, but I decided to copy it anyway, so the post is not dependent on the original.
The function takes a string of characters, and writes down every possible permutat...
For every character in string
...fashioned for-loop:
std::string str = ???;
for(std::string::size_type i = 0; i < str.size(); ++i) {
do_things_with(str[i]);
}
Looping through the characters of a null-terminated character array:
char* str = ???;
for(char* it = str; *it; ++it) {
do_things_with(*it);
}
...
Peak detection in a 2D array
...
+500
I detected the peaks using a local maximum filter. Here is the result on your first dataset of 4 paws:
I also ran it on the second ...
count the frequency that a value occurs in a dataframe column
...['freq'] = df.groupby('a')['a'].transform('count')
df
Out[41]:
a freq
0 a 2
1 b 3
2 s 2
3 s 2
4 b 3
5 a 2
6 b 3
[7 rows x 2 columns]
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