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App Inventor接入Supabase：开源免费的后端新选择 - App Inventor 2 拓展 -...
...客户端）
4. 安装Supabase扩展
在 App Inventor中文网（fun123.cn） 下载Supabase扩展组件，导入到项目中。
5. 配置连接
将Supabase URL和API Key填入扩展组件的对应属性中，即可开始使用。
注意事项
关于匿名登录：Supabase默认没...
5分钟了解 App Inventor 2：不会写代码，也能做出自己的 App - App应用开发...
...5分钟。
中文资源在哪？
App Inventor 2 中文网（www.fun123.cn）提供了：
1. 完整的中文文档：所有组件和积木块都有中文说明
2. 离线版：断网也能用，适合学校机房和培训班
3. 扩展组件：MQTT、Supabase、自定义通知等进阶组件...
第二波Fable5抢收备忘 - 闲聊区 - 清泛IT社区，为创新赋能！
...体删除再加
教育版：优化方向
fun123:优化产品介绍页、文案
滚动条
https://github.com/mit-cml/appin ... tions-6.0.16.min.js 这个是blockly12...
How can I remove 3 characters at the end of a string in php?
How can I remove 3 characters at the end of a string in php? "abcabcabc" would become "abcabc"!
3 Answers
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Best way to check if a URL is valid
I want to use PHP to check, if string stored in $myoutput variable contains a valid link syntax or is it just a normal text. The function or solution, that I'm looking for, should recognize all links formats including the ones with GET parameters.
...
Python way of printing: with 'format' or percent form? [duplicate]
...
Related: bugs.python.org/issue14123
– guettli
Sep 11 '13 at 7:35
Is .format...
How do I get the last inserted ID of a MySQL table in PHP?
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mysql_(...) is deprecated in PHP >= 5.5 version.
– Iago
Oct 30 '14 at 2:12
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AngularJs $http.post() does not send data
... serialization, which unfortunately some Web server languages—notably
PHP—do not unserialize natively.
Works like a charm.
CODE
// Your app's root module...
angular.module('MyModule', [], function($httpProvider) {
// Use x-www-form-urlencoded Content-Type
$httpProvider.defaults.header...
json_encode() escaping forward slashes
...ur enemy)
json_encode($str, JSON_UNESCAPED_SLASHES);
If you don't have PHP 5.4 at hand, pick one of the many existing functions and modify them to your needs, e.g. http://snippets.dzone.com/posts/show/7487 (archived copy).
Example Demo
<?php
/*
* Escaping the reverse-solidus character ("/"...
JavaScript isset() equivalent
In PHP you can do if(isset($array['foo'])) { ... } . In JavaScript you often use if(array.foo) { ... } to do the same, but this is not exactly the same statement. The condition will also evaluate to false if array.foo does exists but is false or 0 (and probably other values as well).
...