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Why is SCTP not much used/known
...nguages (Disclaimer: i'm maintainer of pysctp, SCTP easy stack support for Python)
NAT: Doesn't cross NAT very well/at all (less than 1% internet home & enterprise routers do NAT on SCTP).
Popularity: No general public app use it
Programming paradigm: it changed a bit: it's still a socket, but y...
How to delete the contents of a folder?
How can I delete the contents of a local folder in Python?
24 Answers
24
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Base64Util 拓展:支持图像框、画布、文件、文本字符串、图像精灵base64编...
...码
Base64Util 扩展
下载链接
致谢
注意事项
图像框有关
画布有关
文件有关
文本字符串有关
图像精灵有关
其他可视组件有关
函数
使用示例 ...
Java 反射最佳实践 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...优雅的使用反射。本文的例子都可以在示例代码中看到并下载,如果喜欢请star,如果觉得有纰漏请提交issue,如果你有更好的点子...概要:最简单优雅的使用反射。
本文的例子都可以在示例代码中看到并下载,如果喜欢请star,...
What does “./bin/www” do in Express 4.x?
...ems like a long time ago it evolved to mean anything executable. Common in Python, Perl, and unix/linux in general.
– regularmike
Nov 19 '14 at 14:45
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App Inventor 2 试验组件 · App Inventor 2 中文网
...),编译为apk则不受限制安装后可正常运行。
demo程序下载:
chatgpt.aia
属性
ApiKey
ChatGPT 的 ApiKey,由用户提供。如果提供,我们将使用它来代替聊天代理服务中的 API 密钥。
注意:我们不将其作为属性在“界面设计”...
How can I extract embedded fonts from a PDF as valid font files?
...ed to have some know-how about internal PDF structures. pdf-parser.py is a Python script which can do a lot of other things too. It can also decompress and extract arbitrary streams from objects, and therefore it can extract embedded font files too.
But you need to know what to look for. Let's see i...
StatusbarTools 扩展 - 状态栏自定义工具 · App Inventor 2 中文网
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StatusbarTools 扩展
扩展下载
功能概述
属性
方法
使用示例
基本颜色设置
透明状态栏
全屏模式
动态颜色切换
应用场景 ...
Nginx serves .php files as downloads, instead of executing them
...nages this communication. CGIs can be implemented in any possible language Python (uWSGI), PHP (FPM) and even C. FastCGI is basically an upgraded version of CGI which is much much faster than CGI.
For some, servers like Apache, there is built in support to interpret PHP and thus no need for a CGI...
Code Golf: Collatz Conjecture
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Python - 95 64 51 46 char
Obviously does not produce a stack overflow.
n=input()
while n>1:n=(n/2,n*3+1)[n%2];print n
share
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