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Makefiles with source files in different directories
I have a project where the directory structure is like this:
10 Answers
10
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How to get full path of a file?
Is there an easy way I can print the full path of file.txt ?
32 Answers
32
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CodeIgniter: Create new helper?
I need to loop lot of arrays in different ways and display it in a page. The arrays are generated by a module class. I know that its better not to include functions on 'views' and I want to know where to insert the functions file.
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What's the difference between passing by reference vs. passing by value?
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First and foremost, the "pass by value vs. pass by reference" distinction as defined in the CS theory is now obsolete because the technique originally defined as "pass by reference" has since fallen out of favor and is seldom used now.1
Newer langua...
Java associative-array
How can I create and fetch associative arrays in Java like I can in PHP?
15 Answers
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Why Func instead of Predicate?
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While Predicate has been introduced at the same time that List<T> and Array<T>, in .net 2.0, the different Func and Action variants come from .net 3.5.
So those Func predicates are used mainly for consistency in the LI...
C++11 reverse range-based for-loop
Is there a container adapter that would reverse the direction of iterators so I can iterate over a container in reverse with range-based for-loop?
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[精华] VC中BSTR、Char和CString类型的转换 - C/C++ - 清泛网 - 专注C/C++及内核技术
...::format进行。例如：
char chArray[] = "This is a test";
char * p = "This is a test";
或
LPSTR p = "This is a test";
或在已定义Unicode应的用程序中
TCHAR * p = _T("This is a test");
或
LPTSTR p = _T("This is a test");
CString theString = chArray;
theString.format...
Remove rows with all or some NAs (missing values) in data.frame
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Also check complete.cases :
> final[complete.cases(final), ]
gene hsap mmul mmus rnor cfam
2 ENSG00000199674 0 2 2 2 2
6 ENSG00000221312 0 1 2 3 2
na.omit is nicer for just removing all NA's...
Cast an instance of a class to a @protocol in Objective-C
I have an object (a UIViewController) which may or may not conform to a protocol I've defined.
2 Answers
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