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How can I get column names from a table in SQL Server?
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You can obtain this information and much, much more by querying the Information Schema views.
This sample query:
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = N'Customers'
Can be made over all these DB objects:
CHECK_CONSTRAINTS
COL...
What is the difference between a 'closure' and a 'lambda'?
Could someone explain? I understand the basic concepts behind them but I often see them used interchangeably and I get confused.
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View the Task's activity stack
I just started developing a simple Android application while I'm still learning the platform.
9 Answers
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Android Endless List
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One solution is to implement an OnScrollListener and make changes (like adding items, etc.) to the ListAdapter at a convenient state in its onScroll method.
The following ListActivity shows a list of integers, starting with 40, adding items when the user scrolls to the end...
What is the advantage of using forwarding references in range-based for loops?
...dvantage I can see is when the sequence iterator returns a proxy reference and you need to operate on that reference in a non-const way. For example consider:
#include <vector>
int main()
{
std::vector<bool> v(10);
for (auto& e : v)
e = true;
}
This doesn't compi...
How to create arguments for a Dapper query dynamically
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Note that you can do new DynamicParameters(dictionary) and it will work just fine.
– asgerhallas
Dec 5 '12 at 10:19
1
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How to print out the contents of a vector?
... a supplement to the above iterator solution. If you are using the C++11 standard (or later), then you can use the auto keyword to help the readability:
for (auto i = path.begin(); i != path.end(); ++i)
std::cout << *i << ' ';
But the type of i will be non-const (i.e., the compiler ...
rbenv not changing ruby version
...ub directions. I am running OSX but I have tried this on a Ubuntu 12.04 VM and got the same results. The following is what i get in my terminal when I try to change ruby versions:
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How to remove an element from a list by index
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Use del and specify the index of the element you want to delete:
>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> del a[-1]
>>> a
[0, 1, 2, 3, 4, 5, 6, 7, 8]
Also supports slices:
>>> del a[2:4]
>...
Convert nullable bool? to bool
...in a 'Quick Action' for a Linq statement 'Where' clause, I couldn't understand why lifted operators didn't seem to work inside Linq (perhaps it's just VB.NET?) - I have just tested and it does throw an invalid cast exception
– Luke T O'Brien
Mar 9 '17 at 9:38
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