大约有 47,000 项符合查询结果(耗时:0.0625秒) [XML]

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Finding diff between current and last version

... 1214 I don't really understand the meaning of "last version". As the previous commit can be accessed...
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How do we count rows using older versions of Hibernate (~2009)?

... | edited Nov 4 '18 at 18:58 Alex R 9,6971010 gold badges6666 silver badges133133 bronze badges ...
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How to smooth a curve in the right way?

... | edited Jul 12 '18 at 0:41 dopexxx 1,2071313 silver badges2020 bronze badges answered Dec 17 '13 at 19...
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Android selector & text color

... 406 I got by doing several tests until one worked, so: res/color/button_dark_text.xml <?xml ve...
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What does Ruby have that Python doesn't, and vice versa?

... 34 votes Ruby has the concepts of blocks, which are essentially syntactic sugar around...
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Efficiency of Java “Double Brace Initialization”?

... 16:35 1,919 DemoApp2$11.class 2009/05/27 16:35 2,404 DemoApp2$12.class 2009/05/27 16:35 1,197 DemoApp2$13.class /* snip */ 2009/05/27 16:35 1,953 DemoApp2$30.class 2009/05/27 16:35 1,910 DemoApp2$31.class 2009/05/27 16:35 ...
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Is there a way to do repetitive tasks at intervals?

... 245 The function time.NewTicker makes a channel that sends a periodic message, and provides a way t...
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Tracking CPU and Memory usage per process

... | edited Jun 29 '12 at 0:41 Marquis of Lorne 282k3131 gold badges256256 silver badges424424 bronze badges ...
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Cleanest way to write retry logic?

...nt result = Retry.Do(SomeFunctionWhichReturnsInt, TimeSpan.FromSeconds(1), 4); Or you could even make an async overload. share | improve this answer | follow ...
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Getting random numbers in Java [duplicate]

...util.Random; Random rand = new Random(); // Obtain a number between [0 - 49]. int n = rand.nextInt(50); // Add 1 to the result to get a number from the required range // (i.e., [1 - 50]). n += 1; Another solution is using Math.random(): double random = Math.random() * 49 + 1; or int random ...