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List of installed gems?
... Gem::Requirement.default)
specs = Gem.source_index.search(dep)
puts specs[0..5].map{ |s| "#{s.name} #{s.version}" }
# >> Platform 0.4.0
# >> abstract 1.0.0
# >> actionmailer 3.0.5
# >> actionpack 3.0.5
# >> activemodel 3.0.5
# >> activerecord 3.0.5
Here's an ...
Decreasing for loops in Python impossible?
...
220
for n in range(6,0,-1):
print n
# prints [6, 5, 4, 3, 2, 1]
...
Is there an equivalent for var_dump (PHP) in Javascript?
...
220
As the others said, you can use Firebug, and that will sort you out no worries on Firefox. Chrom...
Creating a UIImage from a UIColor to use as a background image for UIButton [duplicate]
... (UIImage *)imageFromColor:(UIColor *)color {
CGRect rect = CGRectMake(0, 0, 1, 1);
UIGraphicsBeginImageContext(rect.size);
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextSetFillColorWithColor(context, [color CGColor]);
CGContextFillRect(context, rect);
UIImag...
“CASE” statement within “WHERE” clause in SQL Server 2008
...ery which contains "CASE" statement within "WHERE" clause. But SQL Server 2008 is giving some errors while executing it. Can anyone please help me with the correct query? Here is the query:
...
jQuery: checking if the value of a field is null (empty)
...
170
The value of a field can not be null, it's always a string value.
The code will check if the st...
Named colors in matplotlib
..._names)
ncols = 4
nrows = n // ncols
fig, ax = plt.subplots(figsize=(12, 10))
# Get height and width
X, Y = fig.get_dpi() * fig.get_size_inches()
h = Y / (nrows + 1)
w = X / ncols
for i, name in enumerate(sorted_names):
row = i % nrows
col = i // nrows
y = Y - (row * h) - h
xi_li...
How can I split and parse a string in Python?
I am trying to split this string in python: 2.7.0_bf4fda703454
3 Answers
3
...
Check if a value is within a range of numbers
...e. You don't need "multiple if" statements to do it, either:
if (x >= 0.001 && x <= 0.009) {
// something
}
You could write yourself a "between()" function:
function between(x, min, max) {
return x >= min && x <= max;
}
// ...
if (between(x, 0.001, 0.009)) {
//...