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C语言程序判断一个浮点型的数是否为零 - C/C++ - 清泛网 - 专注C/C++及内核技术

C语言程序判断一个浮点型的数是否为零f > -1e-7 && f < 1e-7详细原理请参见:《浮点数在内存中的表示》。f > -1e-7 && f < 1e-7 详细原理请参见:《浮点数在内存中的表示》。浮点型 为零
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c语言字符串常量内容是否可以通过指针修改 - C/C++ - 清泛网 - 专注C/C++及内核技术

c语言字符串常量内容是否可以通过指针修改答案是:不行。尝试修改的话,运行时程序会崩溃。int main(){ char str1[40]="hello world!"; char *str1="hello world!"...答案是:不行。尝试修改的话,运行时程序会崩溃。 int main() { char str...
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/usr/include/c++/4.9/bits/stl_iterator_base_types.h:165:53: error: ‘i...

/usr/include/c++/4.9/bits/stl_iterator_base_types.h:165:53: error: ‘int’ is not a class, struct, or union type先看下面的代码(来自:SO):#include <iostream>#include <cmath>#include <vector>using namespace std;double distance(int a, in...先看下面的代码(来自: SO): #include <i...
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ifstream 线程安全读文件 - C/C++ - 清泛网 - 专注C/C++及内核技术

...etline:std::istream& safeGetline(std::istream& is, std::string& t){ t clear(); 使用std::streambuf 函数 safeGetline: std::istream& safeGetline(std::istream& is, std::string& t) { t.clear(); //这比使用std::istream逐个读取它们要快。 //以这种方式使...
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c++11 std::call_once只调用一次函数,类似单例模式 - C/C++ - 清泛网 - 专...

c++11 std::call_once只调用一次函数,类似单例模式std_call_oncestd::call_once 保证函数或者一些代码段在并发或者多线程的情况下,始终只会被执行一次,Demo如下: include <iostream> include <thread>static std::once_flag g_once_flag std::call_once 保证...
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How to access environment variable values?

... 3337 Environment variables are accessed through os.environ import os print(os.environ['HOME']) ...
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Are C++ enums signed or unsigned?

... answered Oct 1 '08 at 18:38 zvrbazvrba 22.8k33 gold badges5151 silver badges6464 bronze badges ...
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Why does 2 mod 4 = 2?

...| edited Aug 29 '09 at 17:33 Joe Phillips 43k2424 gold badges8989 silver badges147147 bronze badges answ...
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How to get a random value from dictionary in python

...l work in Python 2.x where d.keys() is a list, but it won't work in Python 3.x where d.keys() is an iterator. You should do random.choice(list(d.keys())) instead. – Duncan Feb 1 '11 at 9:42 ...
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Is < faster than

... 1731 No, it will not be faster on most architectures. You didn't specify, but on x86, all of the int...