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Why dict.get(key) instead of dict[key]?
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What are namespaces?
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answered Aug 2 '10 at 1:03
cbednarskicbednarski
10.7k33 gold badges2222 silver badges3333 bronze badges
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bundle install returns “Could not locate Gemfile”
...in /opt/
– Mo Beigi
Nov 7 '15 at 11:06
Just add some clearance that move to the project folder, not 'bin' folder of th...
Kill process by name?
...itlines():
... if 'iChat' in line:
... pid = int(line.split(None, 1)[0])
... os.kill(pid, signal.SIGKILL)
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(you could avoid importing signal, and use 9 instead of signal.SIGKILL, but I just don't particularly like that style, so I'd rather used the named constant this way).
Of cours...
Why does .NET use banker's rounding as default?
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answered Nov 22 '08 at 19:57
KibbeeKibbee
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SLF4J: Failed to load class “org.slf4j.impl.StaticLoggerBinder”. error
...ing the m2e to version 1.1. By removing m2e 1.1 and rolling back to m2e 1.0 everything worked fine. I tried to repeat the problem in Windows and Ubuntu and it gave me the exact same error. Numerous configurations of the slf4j-api and logback were tested but none seem to work.
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How to use UIScrollView in Storyboard
I have a scroll view with content that is 1000px tall and would like to be able to lay it out for easy design on the storyboard.
I know it can be done programmatically but I really want to be able to see it visually. Every time I put a scroll view on a view controller it won't scroll. Is it possib...
How to get started with developing Internet Explorer extensions?
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+500
[UPDATE] I'm updating this answer to work with Internet Explorer 11, in Windows 10 x64 with Visual Studio 2017 Community.
The previou...
Caveats of select/poll vs. epoll reactors in Twisted
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190
For very small numbers of sockets (varies depending on your hardware, of course, but we're talki...
What are the typical reasons Javascript developed on Firefox fails on IE? [closed]
...on.
Base JavaScript language:
Access characters in strings: 'string'[0] isn’t supported in IE as it’s not in the original JavaScript specifications. Use 'string'.charAt(0) or 'string'.split('')[0] noting that accessing items in arrays is significantly faster than using charAt with strings ...