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Splitting a list into N parts of approximately equal length
...ge(10), 3)
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
>>> chunkIt(range(11), 3)
[[0, 1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
>>> chunkIt(range(12), 3)
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
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How do I determine whether an array contains a particular value in Java?
...generic.
– CromTheDestroyer
Jun 14 '11 at 16:51
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jQuery hasAttr checking to see if there is an attribute on an element [duplicate]
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edited Jun 18 '14 at 11:12
Andreas Furster
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Configure Flask dev server to be visible across the network
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edited Oct 11 '17 at 0:19
davidism
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How do I sort an observable collection?
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answered Dec 22 '09 at 11:07
AndrewAndrew
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Change the image source on rollover using jQuery
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jemmamariex3
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answered Feb 12 '09 at 7:31
Jarrod Dixon♦Jarrod Dixon
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Iterate through object properties
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Where can I find Android source code online? [closed]
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edited Dec 11 '19 at 6:52
jajube
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answered Jan 16 '09 at 7:58
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Regex Match all characters between two strings
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edited May 24 '11 at 20:25
answered May 24 '11 at 12:05
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Set type for function parameters?
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answered Dec 6 '11 at 22:16
pronvitpronvit
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