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filter items in a python dictionary where keys contain a specific string
I'm a C coder developing something in python. I know how to do the following in C (and hence in C-like logic applied to python), but I'm wondering what the 'Python' way of doing it is.
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How to generate keyboard events in Python?
...2 = ctypes.WinDLL('user32', use_last_error=True)
INPUT_MOUSE = 0
INPUT_KEYBOARD = 1
INPUT_HARDWARE = 2
KEYEVENTF_EXTENDEDKEY = 0x0001
KEYEVENTF_KEYUP = 0x0002
KEYEVENTF_UNICODE = 0x0004
KEYEVENTF_SCANCODE = 0x0008
MAPVK_VK_TO_VSC = 0
# msdn.microsoft.com/en-us/library/dd375731
VK...
How do I efficiently iterate over each entry in a Java Map?
...ring, String> entry : map.entrySet()) {
System.out.println(entry.getKey() + "/" + entry.getValue());
}
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How to print binary tree diagram?
How can I print a binary tree in Java so that the output is like:
28 Answers
28
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Permutations in JavaScript?
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Andreas WongAndreas Wong
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How to sort objects by multiple keys in Python?
Or, practically, how can I sort a list of dictionaries by multiple keys?
8 Answers
8
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Syntax for creating a two-dimensional array
...nt[][] multi = new int[5][10];
... which is a short hand for something like this:
int[][] multi = new int[5][];
multi[0] = new int[10];
multi[1] = new int[10];
multi[2] = new int[10];
multi[3] = new int[10];
multi[4] = new int[10];
Note that every element will be initialized to the default valu...
How to swap keys and values in a hash
How do I swap keys and values in a Hash?
6 Answers
6
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How does this print “hello world”?
...o group, then the 5-bits group gets isolated ANDing the number with the mask 31₁₀ = 11111₂ in the sentence l & 31
Now the code maps the 5-bit value to its corresponding 7-bit ascii character. This is the tricky part, check the binary representations for the lowercase
alphabet letters in t...
Correct way to convert size in bytes to KB, MB, GB in JavaScript
...om this: (source)
function bytesToSize(bytes) {
var sizes = ['Bytes', 'KB', 'MB', 'GB', 'TB'];
if (bytes == 0) return '0 Byte';
var i = parseInt(Math.floor(Math.log(bytes) / Math.log(1024)));
return Math.round(bytes / Math.pow(1024, i), 2) + ' ' + sizes[i];
}
Note : This is original c...