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How to initialize all members of an array to the same value?

...'s no easy way. Don't overlook the obvious solution, though: int myArray[10] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 }; Elements with missing values will be initialized to 0: int myArray[10] = { 1, 2 }; // initialize to 1,2,0,0,0... So this will initialize all elements to 0: int myArray[10] = { 0 }...
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How to compare two dates?

...>> present - datetime(2000, 4, 4) datetime.timedelta(4242, 75703, 762105) share | improve this answer | follow | ...
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Summarizing multiple columns with dplyr? [duplicate]

...library(purrrlyr) library(data.table) library(bench) set.seed(123) n <- 10000 df <- data.frame( a = sample(1:5, n, replace = TRUE), b = sample(1:5, n, replace = TRUE), c = sample(1:5, n, replace = TRUE), d = sample(1:5, n, replace = TRUE), grp = sample(1:3, n, replace = TRUE) ) d...
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What's the point of const pointers?

... | edited Feb 27 '14 at 10:24 answered Oct 10 '11 at 15:56 ...
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Remove characters after specific character in string, then remove substring?

... | edited Apr 18 '10 at 1:31 answered Apr 18 '10 at 1:19 ...
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How to find the statistical mode?

...} On my dinky little machine, that can generate & find the mode of a 10M-integer vector in about half a second. If your data set might have multiple modes, the above solution takes the same approach as which.max, and returns the first-appearing value of the set of modes. To return all modes,...
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Look up all descendants of a class in Ruby

... | edited Apr 26 '12 at 10:57 answered Mar 6 '10 at 19:04 ...
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Strings are objects in Java, so why don't we use 'new' to create them?

...once. For example, consider the (contrived) code: for (int i = 0; i < 10; i++) { System.out.println("Next iteration"); } If we didn't have interning of Strings, "Next iteration" would need to be instantiated 10 times, whereas now it will only be instantiated once. ...
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How do I convert uint to int in C#?

...ecked approach ?? – user5528169 Dec 10 '15 at 11:57  |  show...
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How to pull remote branch from somebody else's repo

... | edited Aug 10 '17 at 1:03 answered May 4 '11 at 14:17 ...