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Format number as fixed width, with leading zeros [duplicate]

...teger of width 3: a <- seq(1,101,25) sprintf("name_%03d", a) [1] "name_001" "name_026" "name_051" "name_076" "name_101" Another is formatC and paste: paste("name", formatC(a, width=3, flag="0"), sep="_") [1] "name_001" "name_026" "name_051" "name_076" "name_101" ...
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阿里云物联网平台开通及基础用法 - 创客硬件开发 - 清泛IT社区,为创新赋能!

...中会被替换成对应的名字,例如你在该产品下创建了个 D001 设备,那么该设备的topic就是: /你自己的Product/D001/user/test 在添加产品和创建设备完成后,可以在设备的详情页中获得MQTT协议所需的三元组,点击MQTT连接参数后的...
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How to round a number to n decimal places in Java

...make it so that it does a proper rounding so it will not round 0.0004 to 0.001 – user4919188 Oct 20 '16 at 8:00  |  show 5 more comments ...
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Why use double indirection? or Why use pointers to pointers?

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jQuery if checkbox is checked

... answered Dec 20 '16 at 20:53 DA001DA001 60155 silver badges22 bronze badges ...
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NGINX: upstream timed out (110: Connection timed out) while reading response header from upstream

...stCGI 2017/09/27 13:34:03 [error] 16559#16559: *14381 upstream timed out (110: Connection timed out) while reading response header from upstream, client:xxxxxxxxxxxxxxxxxxxxxxxxx", upstream: "fastcgi://unix:/var/run/php/php5.6-fpm.sock", host: "xxxxxxxxxxxxxxx", referrer: "xxxxxxxxxxxxxxxxxxxx" S...
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What's the best way to parse a JSON response from the requests library?

... each of the elements would still be unicode. – felix001 Jun 1 '13 at 21:43 @felix001: yes, although you can convert a...
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Is < faster than

... Jonathon ReinhartJonathon Reinhart 110k2727 gold badges205205 silver badges283283 bronze badges ...
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How can I request the vibrate permission?

... creative pattern try the star wars theme =D v.vibrate(new long[]{0, 500, 110, 500, 110, 450, 110, 200, 110, 170, 40, 450, 110, 200, 110, 170, 40, 500}, -1); share | improve this answer |...
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Check if a value is within a range of numbers

... You don't need "multiple if" statements to do it, either: if (x &gt;= 0.001 &amp;&amp; x &lt;= 0.009) { // something } You could write yourself a "between()" function: function between(x, min, max) { return x &gt;= min &amp;&amp; x &lt;= max; } // ... if (between(x, 0.001, 0.009)) { // s...