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What is the JavaScript >>> operator and how do you use it?
...doing a bitwise operation with no actual effect, like a rightward-shift of 0 bits >>0, is a quick way to round a number and ensure it is in the 32-bit int range. Additionally, the triple >>> operator, after doing its unsigned operation, converts the results of its calculation to Numbe...
TCP: can two different sockets share a port?
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answered Jun 20 '12 at 23:32
Remy LebeauRemy Lebeau
417k2626 gold badges335335 silver badges578578 bronze badges
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What to use as an initial version? [closed]
I usually start my projects with a version 1.0.0. As soon as I have some stuff together, I release it as 1.0.0 and move on with 1.1.0.
...
How do I list all versions of a gem available at a remote site?
...
205
Well, it was easier than I thought (well, not really, let's say as easy as it should be):
gem ...
Any reason not to use '+' to concatenate two strings?
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edited Jan 10 '16 at 12:44
seriousdev
6,91188 gold badges4040 silver badges5050 bronze badges
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Looping in a spiral
...
Here's my solution (in Python):
def spiral(X, Y):
x = y = 0
dx = 0
dy = -1
for i in range(max(X, Y)**2):
if (-X/2 < x <= X/2) and (-Y/2 < y <= Y/2):
print (x, y)
# DO STUFF...
if x == y or (x < 0 and x == -y) or (x &...
What does the ^ operator do in Java?
...perator.
Let's take 5^6 as example:
(decimal) (binary)
5 = 101
6 = 110
------------------ xor
3 = 011
This the truth table for bitwise (JLS 15.22.1) and logical (JLS 15.22.2) xor:
^ | 0 1 ^ | F T
--+----- --+-----
0 | 0 1 F | F T
1 | 1 0 T | T...
Understanding “randomness”
...ough a pseudo-random variable:
BarChart[BinCounts[RandomReal[{0, 1}, 50000], 0.01]]
While this is the distribution you get after multiplying two random variables:
BarChart[BinCounts[Table[RandomReal[{0, 1}, 50000] *
RandomReal[{0, 1}, 500...
How to validate an email address in JavaScript
...^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
return re.test(String(email).toLowerCase());
}
Here's the example of regular expresion that accepts unicode:
const re = /^(([^<&...
