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How to extract year and month from date in PostgreSQL without using to_char() function?
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date_part(text, timestamp)
e.g.
date_part('month', timestamp '2001-02-16 20:38:40'),
date_part('year', timestamp '2001-02-16 20:38:40')
http://www.postgresql.org/docs/8.0/interactive/functions-datetime.html
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format statement in a string resource file
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edited Oct 24 '16 at 9:26
Sufian
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Select first 4 rows of a data.frame in R
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– Eduardo Leoni
May 28 '18 at 21:16
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Unicode, UTF, ASCII, ANSI format differences
What is the difference between the Unicode , UTF8 , UTF7 , UTF16 , UTF32 , ASCII , and ANSI encodings?
2 Answers
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How to get a substring of text?
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edited Oct 21 '16 at 9:41
William Leung
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answered Ma...
Git commit date
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edited May 16 '18 at 11:27
Tyr
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answered Sep 28 '10 at ...
Why should a function have only one exit-point? [closed]
...? 0 : ERR_NOT_OK;
– Melebius
Nov 7 '16 at 11:24
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The first example has a return at the start bef...
Difference between using Throwable and Exception in a try catch
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answered Feb 16 '10 at 15:50
YishaiYishai
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What happens if a Android Service is started multiple times?
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The Service will only run in one instance. However, everytime you start the service, the onSta...
What is the Sign Off feature in Git for?
...but maybe I am wrong.
– hdl
Feb 29 '16 at 10:21
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“Sign-off is a line at the end of the commit ...