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pandas: filter rows of DataFrame with operator chaining

... boolean index. In [96]: df Out[96]: A B C D a 1 4 9 1 b 4 5 0 2 c 5 5 1 0 d 1 3 9 6 In [99]: df[(df.A == 1) & (df.D == 6)] Out[99]: A B C D d 1 3 9 6 If you want to chain methods, you can add your own mask method and use that one. In [90]: def mask(df, key, ...
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Suppress warning CS1998: This async method lacks 'await'

... 107 I've got an interface with some async functions. Methods returning Task, I believe. async ...
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Empty arrays seem to equal true and false at the same time

... d_ethier 3,6042020 silver badges3030 bronze badges answered Mar 30 '11 at 20:10 wildcardwildcard ...
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Sorting 1 million 8-decimal-digit numbers with 1 MB of RAM

... 720 +200 There is...
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How can I check which version of Angular I'm using?

... itself. Header of the current angular.js: /** * @license AngularJS v1.0.6 * (c) 2010-2012 Google, Inc. http://angularjs.org * License: MIT */ share | improve this answer | ...
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How are the points in CSS specificity calculated

... algorithm is 256 or 28. What this means is that a style specified with 0 ids and 256 class-names will over-ride a style specified with just 1 id. I tested this out with some fiddles: 255 classes are not enough to override 1 id ...but 256 classes are enough to override 1 id ...and 256 tag-name...
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Using numpy to build an array of all combinations of two arrays

... 10 Answers 10 Active ...
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Are Javascript arrays sparse?

... 40 How exactly JavaScript arrays are implemented differs from browser to browser, but they generall...
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Which is faster in Python: x**.5 or math.sqrt(x)?

... math.sqrt(x) is significantly faster than x**0.5. import math N = 1000000 %%timeit for i in range(N): z=i**.5 10 loops, best of 3: 156 ms per loop %%timeit for i in range(N): z=math.sqrt(i) 10 loops, best of 3: 91.1 ms per loop Using Python 3.6....
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Find XOR of all numbers in a given range

...ven a large range [a,b] where 'a' and 'b' can be typically between 1 and 4,000,000,000 inclusive. You have to find out the XOR of all the numbers in the given range. ...