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Maven equivalent for python [closed]
I'm a java developer/python beginner, and I'm missing my maven features, particularly dependency management and build automation (I mean you don't build, but how to create a package for deployment?)
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How can I parse a YAML file in Python
How can I parse a YAML file in Python?
7 Answers
7
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Commenting code in Notepad++
I'm using Notepad++ as an editor to write programs in Python. It might sound daft but I looked around in the editor and could not find any means (not the manual way but something like in Emacs) to do a block comment in my code.
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How do I perform HTML decoding/encoding using Python/Django?
... More generally, it is a good idea to stick with the standard library:
# Python 2.x:
import HTMLParser
html_parser = HTMLParser.HTMLParser()
unescaped = html_parser.unescape(my_string)
# Python 3.x:
import html.parser
html_parser = html.parser.HTMLParser()
unescaped = html_parser.unescape(my_stri...
Sending mail from Python using SMTP
I'm using the following method to send mail from Python using SMTP. Is it the right method to use or are there gotchas I'm missing ?
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Comparison of full text search engine - Lucene, Sphinx, Postgresql, MySQL?
...s guy, so I've no idea how easy it is to implement with Django. There is a Python API that comes with the Sphinx source though.
The search service daemon (searchd) is pretty low on memory usage - and you can set limits on how much memory the indexer process uses too.
Scalability is where my knowledg...
XPath to select multiple tags
...well for me. It seems XPath 2.0 is the default for HTML parsing in lxml on Python 2.
– Martin Burch
Feb 8 '16 at 23:51
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2024年2月17日签到记录贴 - 签到区 - 清泛IT社区，为创新赋能！
...在 2024-02-17 08:57 完成签到,是今天第一个签到的用户,获得随机奖励 小红花 10,另外我还额外获得了 小红花 10.我今天最想说:「每天123456」. 我在 2024-02-17 18:13 完成签到,是今天第2个签到的用户,获得随机奖励 小红花 16,另外我还额外...
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...在 2024-02-19 10:05 完成签到,是今天第一个签到的用户,获得随机奖励 小红花 20,另外我还额外获得了 小红花 10.我今天最想说:「该会员没有填写今日想说内容.」. 我在 2024-02-19 11:14 完成签到,是今天第2个签到的用户,获得随机奖励 小...
水果翻翻翻 · App Inventor 2 中文网
... 帮助 应用介绍
屏幕上有6张卡片，里面随机有三种水果，尝试点击格子翻开卡片，如果第二次翻出一样的水果则继续，否则之前翻出的暂时隐藏，直至6张卡片全部翻出则为胜利。
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