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in javascript, how can i get the last character in a string [duplicate]
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Since in Javascript a string is a char array, you can access the last character by the length of the string.
var lastChar = myString[myString.length -1];
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How do I get the list of keys in a Dictionary?
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List<string> keyList = new List<string>(this.yourDictionary.Keys);
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Count occurrences of a char in a string using Bash
I need to count the number of occurrences of a char in a string using Bash.
7 Answers
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Can I specify a custom location to “search for views” in ASP.NET MVC?
...eValues(ViewLocationExpanderContext context) {}
public IEnumerable<string> ExpandViewLocations(ViewLocationExpanderContext context, IEnumerable<string> viewLocations)
{
return new[]
{
"/AnotherPath/Views/{1}/{0}.cshtml",
"/AnotherPath/View...
Converting between strings and ArrayBuffers
... there a commonly accepted technique for efficiently converting JavaScript strings to ArrayBuffers and vice-versa? Specifically, I'd like to be able to write the contents of an ArrayBuffer to localStorage and to read it back.
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How to sort a list of strings?
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The proper way to sort strings is:
import locale
locale.setlocale(locale.LC_ALL, 'en_US.UTF-8') # vary depending on your lang/locale
assert sorted((u'Ab', u'ad', u'aa'), cmp=locale.strcoll) == [u'aa', u'Ab', u'ad']
# Without using locale.strcoll ...
Ask for User Permission to Receive UILocalNotifications in iOS 8
...ion to show notifications from your app, this applies for both remote/push and local notifications. In Swift you can do it like this,
Update for Swift 2.0
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: NSDictionary?) -> Bool {
// Override point for...
Can't specify the 'async' modifier on the 'Main' method of a console app
... identical usage:
using Nito.AsyncEx;
class Program
{
static void Main(string[] args)
{
AsyncContext.Run(() => MainAsync(args));
}
static async void MainAsync(string[] args)
{
Bootstrapper bs = new Bootstrapper();
var list = await bs.GetList();
}
}...
Is it safe to resolve a promise multiple times?
... rejected), that is it for a defered object - it is done.
If you should call then(...) on it's promise again, you should immediately get the (first) resolved/rejected result.
Additional calls to resolve() will not (should not?) have any effect. Not sure what happens if you attempt to reject a de...
Creating an empty bitmap and drawing though canvas in Android
I'd like to create an empty bitmap and set a canvas to that bitmap and then draw any shape on the bitmap.
2 Answers
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