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使用App Inventor扩展实现多点触控:Rotation Detector · App Inventor 2 中文网
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使用App Inventor扩展实现多点触控:Rotation Detector
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Using App Inventor extensions to implement multitouch: Rotation Detector
Xinyue Deng dengxinyue0420@gmail.com
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使用App Inventor扩展实现多点触控:Rotation Detector · App Inventor 2 中文网
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使用App Inventor扩展实现多点触控:Rotation Detector
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Using App Inventor extensions to implement multitouch: Rotation Detector
Xinyue Deng dengxinyue0420@gmail.com
DRAFT...
使用App Inventor扩展实现多点触控:Rotation Detector · App Inventor 2 中文网
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使用App Inventor扩展实现多点触控:Rotation Detector
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Using App Inventor extensions to implement multitouch: Rotation Detector
Xinyue Deng dengxinyue0420@gmail.com
DRAFT...
使用App Inventor扩展实现多点触控:Rotation Detector · App Inventor 2 中文网
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使用App Inventor扩展实现多点触控:Rotation Detector
« 返回首页
Using App Inventor extensions to implement multitouch: Rotation Detector
Xinyue Deng dengxinyue0420@gmail.com
DRAFT...
How to concatenate twice with the C preprocessor and expand a macro as in “arg ## _ ## MACRO”?
I am trying to write a program where the names of some functions are dependent on the value of a certain macro variable with a macro like this:
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How to get a dependency tree for an artifact?
dependency:tree can be used to see the dependency tree for a given project. But what I need is to see the dependency tree for a 3rd party artifact.
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How to join strings in Elixir?
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If you just want to join some arbitrary list:
"StringA" <> " " <> "StringB"
or just use string interpolation:
"#{a} #{b}"
If your list size is arbitrary:
Enum.join(["StringA", "StringB"], " ")
... all of the solutions ab...
Clojure: reduce vs. apply
...erms of the ultimate result returned) for associative functions which need to see all their arguments in the variable-arity case. When they are result-wise equivalent, I'd say that apply is always perfectly idiomatic, while reduce is equivalent -- and might shave off a fraction of a blink of an eye ...
AJAX in Chrome sending OPTIONS instead of GET/POST/PUT/DELETE?
... site is served on localhost:6120 and the service I'm making AJAX requests to is on 57124. This closed jquery bug defines the issue, but not a real fix.
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How to split a string, but also keep the delimiters?
...ou can use Lookahead and Lookbehind. Like this:
System.out.println(Arrays.toString("a;b;c;d".split("(?<=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("(?=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("((?<=;)|(?=;))")));
And you will get:
[a;, b;, c;, d]
[a, ;b, ;c...
