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HTML Input=“file” Accept Attribute File Type (CSV)
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edited Mar 30 '16 at 5:15
Rikin Patel
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answe...
How to generate a random number in C++?
...gned long j;
srand( (unsigned)time(NULL) );
for( j = 0; j < 100500; ++j )
{
int n;
/* skip rand() readings that would make n%6 non-uniformly distributed
(assuming rand() itself is uniformly distributed from 0 to RAND_MAX) */
while( ( n = rand() ) &g...
Is there a case insensitive jQuery :contains selector?
... :contains selector remains unchanged.
Edit: For jQuery 1.3 (thanks @user95227) and later you need
jQuery.expr[':'].Contains = function(a,i,m){
return jQuery(a).text().toUpperCase().indexOf(m[3].toUpperCase())>=0;
};
Edit:
Apparently accessing the DOM directly by using
(a.textContent |...
Remove multiple elements from array in Javascript/jQuery
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258
There's always the plain old for loop:
var valuesArr = ["v1","v2","v3","v4","v5"],
removeV...
MetadataException: Unable to load the specified metadata resource
...tephen Turner
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answered Mar 27 '09 at 12:02
Craig StuntzCraig Stuntz
123k12...
Explain the use of a bit vector for determining if all characters are unique
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for int you will have lower-level bit logic code:
checker |= (1 << 5); // set flag at index 5 to true
Also probably int may be a little bit faster, because operations with bits are very low level and can be executed as-is by CPU. BitVector allows writing a little bit less cryptic code inst...
Patterns for handling batch operations in REST web services?
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AlexAlex
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...
RegEx for Javascript to allow only alphanumeric
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528
/^[a-z0-9]+$/i
^ Start of string
[a-z0-9] a or b or c or ... z or 0 or 1 or ... 9
+ ...
Which Eclipse version should I use for an Android app?
...pse ADT plugin is no longer supported, as per this announcement in June 2015.
The Eclipse ADT plugin has many known bugs and potential security bugs that will not be fixed.
You should immediately switch to use Android Studio, the official IDE for Android. For help transitioning your projects, read...
Pandas DataFrame Groupby two columns and get counts
...y @Andy's answer, you can do following to solve your second question:
In [56]: df.groupby(['col5','col2']).size().reset_index().groupby('col2')[[0]].max()
Out[56]:
0
col2
A 3
B 2
C 1
D 3
share
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