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Extract directory from path
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dirname $file
is what you are looking for
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How to return value from an asynchronous callback function? [duplicate]
This question is asked many times in SO. But still I can't get stuff.
3 Answers
3
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Backbone.js: How to get the index of a model in a Backbone Collection?
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yes, backbone provides access to many underscore.js methods on models and collections, including an indexOf method on collections. it also provides an at method like you've shown.
var index = this.collection.indexOf(this.model);
var modelAbove = this.collection.at(index-1);
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javascript pushing element at the beginning of an array [duplicate]
I have an array of objects and I'd like to push an element at the beginning of the of the array.
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Facebook Access Token for Pages
I have a Facebook Page that I want to get some things from it. First thing are feeds and from what I read they are public (no need for access_token). But I want to also get the events... and they aren't public and need the access_token.
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Is there a way to programmatically tell if particular block of memory was not freed by FastMM?
I am trying to detect if a block of memory was not freed. Of course, the manager tells me that by dialog box or log file, but what if I would like to store results in a database? For example I would like to have in a database table a names of routines which allocated given blocks.
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Bash mkdir and subfolders [duplicate]
Why I can't do something like this? mkdir folder/subfolder/ in order to achive this I have to do:
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Exported service does not require permission: what does it mean?
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I had the same issue when I updated SDK to version 20. I removed it adding android:exported property android:exported="false" like so:
<service android:name=".MyService"
android:exported="false">
<intent-filter>
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See what's in a stash without applying it [duplicate]
... run
git stash show -p
To view the content of an arbitrary stash, run something like
git stash show -p stash@{1}
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Python initializing a list of lists [duplicate]
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The problem is that they're all the same exact list in memory. When you use the [x]*n syntax, what you get is a list of n many x objects, but they're all references to the same object. They're not distinct instances, rather, just n references to the same instance...