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Bash: If/Else statement in one line

...me_process ) is running on a server. If it is, then echo 1, otherwise echo 0. 5 Answers ...
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What's the fastest way to convert String to Number in JavaScript?

... There are 4 ways to do it as far as I know. Number(x); parseInt(x, 10); parseFloat(x); +x; By this quick test I made, it actually depends on browsers. http://jsperf.com/best-of-string-to-number-conversion/2 Implicit marked the fastest on 3 browsers, but it makes the code hard to read… S...
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How can I get a count of the total number of digits in a number?

... Without converting to a string you could try: Math.Ceiling(Math.Log10(n)); Correction following ysap's comment: Math.Floor(Math.Log10(n) + 1); share | improve this answer | ...
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How do I reverse a C++ vector?

...{ std::vector<int> a; std::reverse(a.begin(), a.end()); return 0; } share | improve this answer | follow | ...
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How to install a previous exact version of a NPM package?

I used nvm to download node v0.4.10 and installed npm to work with that version of node. 10 Answers ...
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Capturing Groups From a Grep RegEx

I've got this little script in sh (Mac OSX 10.6) to look through an array of files. Google has stopped being helpful at this point: ...
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How do you sort an array on multiple columns?

... 170 If owner names differ, sort by them. Otherwise, use publication name for tiebreaker. function m...
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Swift - How to convert String to Double

...e: The NSString doubleValue property is not recommended because it returns 0 if the value cannot be converted (i.e.: bad user input). let lessPrecisePI = Float("3.14") let morePrecisePI = Double("3.1415926536") let invalidNumber = Float("alphabet") // nil, not a valid number Unwrap the values to...
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Get local IP address in node.js

... net of nets[name]) { // skip over non-ipv4 and internal (i.e. 127.0.0.1) addresses if (net.family === 'IPv4' && !net.internal) { if (!results[name]) { results[name] = []; } results[name].push(net.address); } } ...
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Convert a number range to another range, maintaining ratio

...) + NewMin Or if you want to protect for the case where the old range is 0 (OldMin = OldMax): OldRange = (OldMax - OldMin) if (OldRange == 0) NewValue = NewMin else { NewRange = (NewMax - NewMin) NewValue = (((OldValue - OldMin) * NewRange) / OldRange) + NewMin } Note that in this...