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python dataframe pandas drop column using int

... | edited Feb 16 '16 at 10:48 frederikf 333 bronze badges answered Nov 30 '13 at 15:06 ...
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How to sort objects by multiple keys in Python?

...ult: return mult * result else: return 0 return sorted(items, cmp=comparer) You can call it like this: b = [{u'TOT_PTS_Misc': u'Utley, Alex', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'Russo, Brandon', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'...
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What are best practices for validating email addresses on iOS 2.0

... the cleanest way to validate an email address that a user enters on iOS 2.0? 13 Answers ...
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How to get all subsets of a set? (powerset)

..., you can just change the range statement to range(1, len(s)+1) to avoid a 0-length combination. share | improve this answer | follow | ...
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How to round up to the nearest 10 (or 100 or X)?

... If you just want to round up to the nearest power of 10, then just define: roundUp <- function(x) 10^ceiling(log10(x)) This actually also works when x is a vector: > roundUp(c(0.0023, 3.99, 10, 1003)) [1] 1e-02 1e+01 1e+01 1e+04 ..but if you want to round to a "nice"...
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Int division: Why is the result of 1/3 == 0?

...se returns the true result of division rounded towards zero. The result of 0.333... is thus rounded down to 0 here. (Note that the processor doesn't actually do any rounding, but you can think of it that way still.) Also, note that if both operands (numbers) are given as floats; 3.0 and 1.0, or eve...
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Replace only some groups with Regex

... answered May 15 '11 at 0:13 bluepnumebluepnume 13.1k88 gold badges3232 silver badges4444 bronze badges ...
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Is 1.0 a valid output from std::generate_canonical?

...o and one, without 1 , i.e. they are numbers from the half-open interval [0,1). The documention on cppreference.com of std::generate_canonical confirms this. ...
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What does the constant 0.0039215689 represent?

... 0.0039215689 is approximately equal to 1/255. Seeing that this is OpenGL, performance is probably important. So it's probably safe to guess that this was done for performance reasons. Multiplying by the reciprocal is faster...
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How to compare times in Python?

...datetime.datetime.now() >>> today8am = now.replace(hour=8, minute=0, second=0, microsecond=0) >>> now < today8am True >>> now == today8am False >>> now > today8am False share ...